Question

我的清单中有互联网权限，我试图在我的网页浏览的搜索栏上搜索“facebook”，但问题是，对于50％的搜索，它不会加载搜索请求！这太奇怪了，令人沮丧。我正确地实现了一切，并检查了一切3次，但没有运气。每次我在其他浏览器上搜索相同的内容时，它总是有效。但是当我在我的webview上搜索时，它有时会加载页面，并且大多数时候，进度条显示加载，并且就像页面实际加载一样消失，但它仍然是白色的。为什么会这样？

public class MainActivity extends AppCompatActivity {
private EditText searchEditText;
private ProgressBar progressBar;
private WebView webView;
private String SearchString = "https://www.google.co.in/search?q=";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    progressBar = (ProgressBar) findViewById(R.id.progressBar);
    progressBar.setMax(100);
    webView = (WebView) findViewById(R.id.webView);
    webView.setWebViewClient(new WebViewClientDemo());
    webView.setWebChromeClient(new WebChromeClientDemo());
    webView.getSettings().setJavaScriptEnabled(true);
    webView.loadUrl("about:blank");
    // use keyboard go button to search
    searchEditText = (EditText) findViewById(R.id.searchfield);
    searchEditText.setOnEditorActionListener(new TextView.OnEditorActionListener() {
        public boolean onEditorAction(TextView arg0, int arg1, KeyEvent arg2) {
            CustomSearch();
            return false;
        }
    });
}

private class WebViewClientDemo extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        view.loadUrl(url);
        return true;
    }

    @Override
    public void onPageFinished(WebView view, String url) {
        super.onPageFinished(view, url);
        progressBar.setVisibility(View.GONE);
        progressBar.setProgress(100);
    }

    @Override
    public void onPageStarted(WebView view, String url, Bitmap favicon) {
        super.onPageStarted(view, url, favicon);
        progressBar.setVisibility(View.VISIBLE);
        progressBar.setProgress(0);
    }

    @Override
    public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
        Toast.makeText(getBaseContext(), "page error. please try again!", Toast.LENGTH_SHORT).show();
        super.onReceivedError(view, errorCode, description, failingUrl);
    }
}

private class WebChromeClientDemo extends WebChromeClient {
    public void onProgressChanged(WebView view, int progress) {
        progressBar.setProgress(progress);
}

 public void CustomSearch() {
    searchEditText = (EditText) findViewById(R.id.searchfield);
    String url = searchEditText.getText().toString();
    url = SearchString + url.replace(" ", "+");// replace_spaces_with_a_"+"_sign(prefix)
    webView.loadUrl(url);
}

Answer 1

您是否尝试对搜索文本进行编码，根据我的理解，您需要对搜索字符串进行编码。

为什么webview并不总是有效？

1 个答案: