我正在尝试实现一个安全版本的std :: shared_ptr,名为“safe_ptr”,保证“非null”。
编辑:删除了问题。如果感兴趣,请参见编向感兴趣的人发布最终解决方案:
此代码现在托管在google code。
#pragma once
#include <memory>
#include <type_traits>
#include <exception>
template<typename T>
class safe_ptr
{
template <typename> friend class safe_ptr;
public:
typedef T element_type;
safe_ptr() : impl_(std::make_shared<T>()){}
safe_ptr(const safe_ptr<T>& other) : impl_(other.impl_){}
template<typename U>
safe_ptr(const safe_ptr<U>& other, typename std::enable_if<std::is_convertible<U*, T*>::value, void*>::type = 0) : impl_(other.impl_){}
template<typename U>
safe_ptr(const U& impl, typename std::enable_if<std::is_convertible<typename std::add_pointer<U>::type, T*>::value, void>::type* = 0)
: impl_(std::make_shared<U>(impl)) {}
template<typename U, typename D>
safe_ptr(const U& impl, D dtor, typename std::enable_if<std::is_convertible<typename std::add_pointer<U>::type, T*>::value, void>::type* = 0)
: impl_(new U(impl), dtor) {}
template<typename U>
safe_ptr(U&& impl, typename std::enable_if<std::is_convertible<typename std::add_pointer<U>::type, T*>::value, void>::type* = 0)
: impl_(std::make_shared<U>(std::forward<U>(impl))) {}
template<typename U, typename D>
safe_ptr(U&& impl, D dtor, typename std::enable_if<std::is_convertible<typename std::add_pointer<U>::type, T*>::value, void>::type* = 0)
: impl_(new U(std::forward<U>(impl)), dtor) {}
template<typename U>
explicit safe_ptr(const std::shared_ptr<U>& impl, typename std::enable_if<std::is_convertible<U*, T*>::value, void*>::type = 0) : impl_(impl)
{
if(!impl_)
throw std::invalid_argument("impl");
}
template<typename U>
explicit safe_ptr(std::shared_ptr<U>&& impl, typename std::enable_if<std::is_convertible<U*, T*>::value, void*>::type = 0) : impl_(std::move(impl))
{
if(!impl_)
throw std::invalid_argument("impl");
}
template<typename U>
explicit safe_ptr(U* impl, typename std::enable_if<std::is_convertible<U*, T*>::value, void*>::type = 0) : impl_(impl)
{
if(!impl_)
throw std::invalid_argument("impl");
}
template<typename U, typename D>
explicit safe_ptr(U* impl, D dtor, typename std::enable_if<std::is_convertible<U*, T*>::value, void*>::type = 0) : impl_(impl, dtor)
{
if(!impl_)
throw std::invalid_argument("impl");
}
template<typename U>
typename std::enable_if<std::is_convertible<U*, T*>::value, safe_ptr<T>&>::type
operator=(const safe_ptr<U>& other)
{
safe_ptr<T> temp(other);
temp.swap(*this);
return *this;
}
template <typename U>
typename std::enable_if<std::is_convertible<typename std::add_pointer<U>::type, T*>::value, safe_ptr<T>&>::type
operator=(U&& impl)
{
safe_ptr<T> temp(std::forward<T>(impl));
temp.swap(*this);
return *this;
}
T& operator*() const { return *impl_.get();}
T* operator->() const { return impl_.get();}
T* get() const { return impl_.get();}
bool unique() const { return impl_.unique();}
long use_count() const { return impl_.use_count();}
void swap(safe_ptr& other) { impl_.swap(other.impl_); }
operator std::shared_ptr<T>() const { return impl_;}
template<class U>
bool owner_before(const safe_ptr<T>& ptr){ return impl_.owner_before(ptr.impl_); }
template<class U>
bool owner_before(const std::shared_ptr<U>& ptr){ return impl_.owner_before(ptr); }
template<class D, class U>
D* get_deleter(safe_ptr<U> const& ptr) { return impl_.get_deleter(); }
private:
std::shared_ptr<T> impl_;
};
template<class T, class U>
bool operator==(const safe_ptr<T>& a, const safe_ptr<U>& b)
{
return a.get() == b.get();
}
template<class T, class U>
bool operator!=(const safe_ptr<T>& a, const safe_ptr<U>& b)
{
return a.get() != b.get();
}
template<class T, class U>
bool operator<(const safe_ptr<T>& a, const safe_ptr<U>& b)
{
return a.get() < b.get();
}
template<class T, class U>
bool operator>(const safe_ptr<T>& a, const safe_ptr<U>& b)
{
return a.get() > b.get();
}
template<class T, class U>
bool operator>=(const safe_ptr<T>& a, const safe_ptr<U>& b)
{
return a.get() >= b.get();
}
template<class T, class U>
bool operator<=(const safe_ptr<T>& a, const safe_ptr<U>& b)
{
return a.get() <= b.get();
}
template<class E, class T, class U>
std::basic_ostream<E, T>& operator<<(std::basic_ostream<E, T>& out, const safe_ptr<U>& p)
{
return out << p.get();
}
template<class T>
void swap(safe_ptr<T>& a, safe_ptr<T>& b)
{
a.swap(b);
}
template<class T>
T* get_pointer(safe_ptr<T> const& p)
{
return p.get();
}
template <class T, class U>
safe_ptr<T> static_pointer_cast(const safe_ptr<U>& p)
{
return safe_ptr<T>(std::static_pointer_cast<T>(std::shared_ptr<U>(p)));
}
template <class T, class U>
safe_ptr<T> const_pointer_cast(const safe_ptr<U>& p)
{
return safe_ptr<T>(std::const_pointer_cast<T>(std::shared_ptr<U>(p)));
}
template <class T, class U>
safe_ptr<T> dynamic_pointer_cast(const safe_ptr<U>& p)
{
auto temp = std::dynamic_pointer_cast<T>(std::shared_ptr<U>(p));
if(!temp)
throw std::bad_cast();
return safe_ptr<T>(temp);
}
template<typename T>
safe_ptr<T> make_safe()
{
return safe_ptr<T>();
}
template<typename T, typename P0>
safe_ptr<T> make_safe(P0&& p0)
{
return safe_ptr<T>(std::make_shared<T>(std::forward<P0>(p0)));
}
template<typename T, typename P0, typename P1>
safe_ptr<T> make_safe(P0&& p0, P1&& p1)
{
return safe_ptr<T>(std::make_shared<T>(std::forward<P0>(p0), std::forward<P1>(p1)));
}
template<typename T, typename P0, typename P1, typename P2>
safe_ptr<T> make_safe(P0&& p0, P1&& p1, P2&& p2)
{
return safe_ptr<T>(std::make_shared<T>(std::forward<P0>(p0), std::forward<P1>(p1), std::forward<P2>(p2)));
}
template<typename T, typename P0, typename P1, typename P2, typename P3>
safe_ptr<T> make_safe(P0&& p0, P1&& p1, P2&& p2, P3&& p3)
{
return safe_ptr<T>(std::make_shared<T>(std::forward<P0>(p0), std::forward<P1>(p1), std::forward<P2>(p2), std::forward<P3>(p3)));
}
template<typename T, typename P0, typename P1, typename P2, typename P3, typename P4>
safe_ptr<T> make_safe(P0&& p0, P1&& p1, P2&& p2, P3&& p3, P4&&)
{
return safe_ptr<T>(std::make_shared<T>(std::forward<P0>(p0), std::forward<P1>(p1), std::forward<P2>(p2), std::forward<P3>(p3), std::forward<P3>(p4)));
}
答案 0 :(得分:4)
你向is_convertible
落后的论据。您想检查Y*
到T*
,表示为:
std::is_convertible<Y*, T*>
关于你的编辑:是的,你需要一个朋友声明
// Within the body of the class
template <typename> friend class safe_ptr; // the syntax is peculiar...
此外,您可能希望为safe_ptr
提供默认构造函数,它自然默认构造对象。我忘记了调用我在上一个问题的答案中指向的对象的默认构造函数:)
答案 1 :(得分:1)
我认为你正在使用is_convertible
反击。尝试
template<typename Y>
safe_ptr(const safe_ptr<Y>& other, typename std::enable_if<std::is_convertible<Y*, T*>::value, void*>::type = 0) : impl_(other.impl_){}
答案 2 :(得分:1)
要访问私人会员impl_
,您必须与safe_ptr
模板的不同实例进行交流。
template <class Y> friend class safe_ptr;
答案 3 :(得分:1)
template<class Y> friend class safe_ptr;