Question

我有这个选择客户的功能

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    getActivity().getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN, WindowManager.LayoutParams.FLAG_FULLSCREEN);
}

用户选择了BMW文件夹或丰田车所以Function GetFolder() As String Dim fldr As FileDialog Set fldr = Application.FileDialog(msoFileDialogFolderPicker) With fldr .Title = "Select" .AllowMultiSelect = False If .Show = 0 Then MsgBox ("Canceled") Exit Function Else: sItem = .SelectedItems(1) GoTo NextCode End If End With NextCode: GetFolder = sItem Set fldr = Nothing End Function
或sItem = "T:\DOCUMENTATION\BMW"

我需要从字符串（sItem = "T:\DOCUMENTATION\TOYOTA"）中提取哪个客户（sItem，BMW）并创建新的提取字符串Toyota

所以结果将是sItemCustomer

你能帮帮我吗？

Answer 1

SPLIT是您所需要的，或者更多的工作，INSTR或INSTRREV和MID或RIGHT

split(sItem,"\")(2)

正确地做＆＃34;

Function pop(strInput As String, Optional strDelim As String = "\") As String
    Dim a() As String
    a = Split(strInput, strDelim)
    pop = a(UBound(a))
    Erase a
End Function

Answer 2

如上所述 Nathan_Sav ，另一种方法是：

sItemCustomer = Right(sItem, Len(sItem) - InStrRev(sItem, "\"))

Answer 3

这是从字符串中提取第n个单词的UDF。只需在第20,21,22行用您的角色替换空格无需费力即可找到最后一个单词的公式也是-= ExtractWord（B2，LEN（B2）-LEN（（SUBSTITUTE（B2，“”，“”）））））或

= ExtractWord（“ STRing”，单词数）

Function ExtractWord(r As Range, WordCoice As Integer)
Dim CompanyName As String 
CompanyName = Trim(r.Value) 
CompanyNameLen = Len(CompanyName) 
CompanyNameWordCount = Len(Trim(CompanyName)) - Len(Replace(Trim(CompanyName), " ", "")) + 1 
If CompanyNameWordCount > 1 Then 
    Choice = WordCoice 
Else 
    ExtractWord = CompanyName 
    Exit Function 
End If 
If Choice > CompanyNameWordCount Or Choice < 1 Then 
    ExtractWord = "#N/A" 
    Exit Function 
Else
WordPos = 1
Count = 1
Do While Count <= Choice
Count = Count + 1
    If InStr(1, CompanyName, " ", vbTextCompare) > 0 Then
        ChosenWord = Mid(CompanyName, 1, InStr(1, CompanyName, " ", vbTextCompare) - 1)
        WordPos = InStr(1, CompanyName, " ", vbTextCompare) + 1 
        CompanyName = Mid(CompanyName, WordPos, CompanyNameLen) 
    Else
        ChosenWord = CompanyName
    End If 
Loop
ExtractWord = ChosenWord
End If
End Function

VBA - 从字符串中提取最后一个单词并从提取中创建新字符串

3 个答案:

= ExtractWord（“ STRing”，单词数）