Question

如果我将年份和月份作为输入（PHP），有没有办法获得前三个月。假设我给出了值，

$month = "2";
$year = 2016;

它应该像下面的数组一样返回，

Array ( [0] => '11 2015' [1] => '12 2015' [2] => '01 2016')

Answer 1

你的意思是这样的吗？

function getLastMonths($year, $month, $format = 'm Y', $amount = 3) {
  $months = [];
  $time = strtotime($year . '-' . $month . '-01 00:00:00');

  for ($i = 1; $i <= $amount; $i++) {
    $months[] = date($format, strtotime('-' . $i . ' month', $time));
  }

  return $months;
}

所以你可以像那样使用它

$month_array = getLastMonths('2017', '06');
var_dump($month_array);

Answer 2

使用// Login Success Authenticate [HttpPost] [AllowAnonymous] [ValidateAntiForgeryToken] public async Task<ActionResult> Login(LoginViewModel model, string returnUrl) { if (!ModelState.IsValid) { return View(model); } // This doesn't count login failures towards account lockout // To enable password failures to trigger account lockout, change to shouldLockout: true var result = await SignInManager.PasswordSignInAsync(model.Email, model.Password, model.RememberMe, shouldLockout: false); switch (result) { case SignInStatus.Success: { // check this section var isGmail = Regex.IsMatch(model.Email, @"^*@g(oogle)?mail\.com$"); if (isGmail) { return View("GmailViewCshtml", model); } else { return RedirectToLocal(returnUrl); }** } case SignInStatus.LockedOut: return View("Lockout"); case SignInStatus.RequiresVerification: return RedirectToAction("SendCode", new { ReturnUrl = returnUrl, RememberMe = model.RememberMe }); case SignInStatus.Failure: default: ModelState.AddModelError("", "Invalid login attempt."); return View(model); } }

mktime

输出

$month = "2";
$year = 2016;

for($i=3;$i>0;$i--){
    $arr[]=date("m-Y", mktime(0, 0, 0, $month-$i, 01, $year));


}
print_r($arr);

对您的评论进行编辑，将Array ( [0] => 11-2015 [1] => 12-2015 [2] => 01-2016 )替换为m

Answer 3

$month = "2";
$year  = 2016;

$result   = [];
$dateTime = DateTime::createFromFormat('Y n', "$year $month");
for($i = 0; $i < 3; $i++) {
    $dateTime->sub(new DateInterval('P1M'));
    $result[] = $dateTime->format('m Y');
}

var_dump(array_reverse($result));

输出

array(3) {
  [0]=>
  string(7) "11 2015"
  [1]=>
  string(7) "12 2015"
  [2]=>
  string(7) "01 2016"
}

Answer 4

试试这段代码：

$array = array();
$month = "2";
$year = 2016;
$number_of_months = 3;
for($i = 0; $i < $number_of_months; $i++):
    $sub_date   = date("m Y", strtotime($year."-".$month." -1 months"));
    $array[]    = $sub_date;
    $month      = explode(" ", $sub_date)[0];
    $year       = explode(" ", $sub_date)[1];
endfor;

print_r($array);

根据给定的月份和年份，获得前三个月的年份

4 个答案: