Question

我必须创建一个REST响应。数据采用json格式，必须按以下结构构建：

{
    "device_id" : { "downlinkData" : "deadbeefcafebabe"}
}

“device_id”必须替换为DeviceId，例如：

{
    "333ee" : { "downlinkData" : "deadbeefcafebabe"}
}

或

{
    "9886y" : { "downlinkData" : "deadbeefcafebabe"}
}

我使用了http://www.jsonschema2pojo.org/，这就是结果：

@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonPropertyOrder({
"device_id"
})
public class DownlinkCallbackResponse {

    @JsonProperty("device_id")
    private DeviceId deviceId;
    @JsonIgnore
    private Map<String, Object> additionalProperties = new HashMap<String, Object>();

    @JsonProperty("device_id")
    public DeviceId getDeviceId() {
    return deviceId;
    }

    @JsonProperty("device_id")
    public void setDeviceId(DeviceId deviceId) {
    this.deviceId = deviceId;
    }

    @JsonAnyGetter
    public Map<String, Object> getAdditionalProperties() {
    return this.additionalProperties;
    }

    @JsonAnySetter
    public void setAdditionalProperty(String name, Object value) {
    this.additionalProperties.put(name, value);
    }

}

和

@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonPropertyOrder({
"downlinkData"
})
public class DeviceId {

    @JsonProperty("downlinkData")
    private String downlinkData;
    @JsonIgnore
    private Map<String, Object> additionalProperties = new HashMap<String, Object>();

    @JsonProperty("downlinkData")
    public String getDownlinkData() {
    return downlinkData;
    }

    @JsonProperty("downlinkData")
    public void setDownlinkData(String downlinkData) {
    this.downlinkData = downlinkData;
    }

    @JsonAnyGetter
    public Map<String, Object> getAdditionalProperties() {
    return this.additionalProperties;
    }

    @JsonAnySetter
    public void setAdditionalProperty(String name, Object value) {
    this.additionalProperties.put(name, value);
    }

}

但基于此POJO，我无法设置deviceID：

DownlinkCallbackResponse downlinkCallbackResponse = new DownlinkCallbackResponse ();

        DeviceId deviceId = new DeviceId();
        deviceId.setDownlinkData(data);     
        downlinkCallbackResponse.setDeviceId(deviceId);

        return new ResponseEntity<>(downlinkCallbackResponse, HttpStatus.OK);

Answer 1

获取以下json字符串

 { "downlinkData" : "deadbeefcafebabe"}

创建json对象（Lib：java-json.jar）

 JSONObject obj = new JSONObject();

将json字符串放在json对象上。

 obj.put("333ee", jsonString);

将创建以下json字符串

{

"333ee" : { "downlinkData" : "deadbeefcafebabe"}
}

我希望这会对你有所帮助。： - ）

JAVA json schema 2 POJO

1 个答案: