从AJAX

Question

我有以下代码从数据库中检索数据：

List<LocationBean> Locations = new ArrayList<LocationBean>();

        /*
         * The following logic iterates through the database entries
         * */

        for(int i = 1; i<=10; ++i){

            String query ="SELECT * FROM Energyinfo.Info WHERE id_number = " +i;
            ResultSet rs = stmt.executeQuery(query);


            while(rs.next()){
                int id = rs.getInt("id_number");
                int kw = rs.getInt("kilowatts_used");
                double lat = rs.getDouble("Latitude");
                double lon = rs.getDouble("Longitude");
                LocationBean temp = new LocationBean(id, kw, lat, lon);
                Locations.add(temp);


        }}
        String jsonData = new Gson().toJson(Locations);
        System.out.println(jsonData);
        response.setContentType("application/json");
        response.setCharacterEncoding("UTF-8");
        response.getWriter().write(jsonData);

我不确定这是否已正确设置为在前端检索。但是，我想在JSP中使用AJAX来检索此JSON对象以在屏幕上显示。我希望这是动态的，因为数据库数据库中的数据可能会发生变化。