d3.js突出显示节点/路径 - 连接的节点不会突出显示

时间:2017-05-31 15:14:35

标签: javascript d3.js

要在点击时突出显示节点和已连接的节点/路径,我将遵循以下示例:http://www.coppelia.io/2014/07/an-a-to-z-of-extra-features-for-the-d3-force-layout/

我插入了这段代码:

  //---Insert-------

  //Toggle stores whether the highlighting is on
  var toggle = 0;

  //Create an array logging what is connected to what
  var linkedByIndex = {};
  for (i = 0; i < data.nodes.length; i++) {
      linkedByIndex[i + "," + i] = 1;
  };
  data.links.forEach(function (d) {
      linkedByIndex[d.source.index + "," + d.target.index] = 1;
  });

  //This function looks up whether a pair are neighbours
  function neighboring(a, b) {
      return linkedByIndex[a.index + "," + b.index];
  }

  function connectedNodes() {

      if (toggle == 0) {
          //Reduce the opacity of all but the neighbouring nodes
          d = d3.select(this).node().__data__;
          circle.style("opacity", function (o) {
              return neighboring(d, o) | neighboring(o, d) ? 1 : 0.1;
          });

          path.style("opacity", function (o) {
              return d.index==o.source.index | d.index==o.target.index ? 1 : 0.1;
          });

          //Reduce the op

          toggle = 1;
      } else {
          //Put them back to opacity=1
          circle.style("opacity", 1);
          path.style("opacity", 1);
          toggle = 0;
      }

  }

我将此行添加到节点:

.on('click', connectedNodes)

结果是,当单击节点时,它的连接路径会正确突出显示,但节点及其连接的节点不会突出显示。相反,所有节点都减少到0.1不透明度。如何更改代码以正确突出显示已连接的节点?

0 个答案:

没有答案
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