这些用于创建表的查询有什么不好?
CREATE TABLE IF NOT EXISTS `CVM`.`CANDIDATE` (
`ID` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT ,
`FULL_NAME` VARCHAR(64) NOT NULL ,
`HR_INTERVIEW_DATE` DATE NULL ,
`JOB_SEARCH_STATUS` TINYINT(1) NULL ,
`REFERENCES_OPTIONAL` TEXT NULL ,
`AVAILABILITY` TEXT NULL ,
`LOCATION` VARCHAR(200) NULL ,
`TRIP` TEXT NULL ,
`INTERPERSONAL_RISKS` TEXT NULL ,
`TECHNICAL_INTERVIEW_DATE` DATE NULL ,
`EXPERIENCE_IT` TINYINT UNSIGNED NULL ,
`EXPERIENCE_JAVA` TINYINT UNSIGNED NULL ,
`ENGLISH_CHECK_DATE` DATE NULL ,
`ENGLISH_READINESS_DIALOGUE` VARCHAR(100) NULL ,
`ENGLISH_TIME_IMPROVMENT` TINYINT UNSIGNED NULL ,
`ENGLISH_LEVEL_ID` INT NULL ,
`LEVEL_ID` INT NULL ,
`DESIRED_POSITIONS` VARCHAR(100) NULL ,
`HR_COMMENT` TEXT NULL ,
`EXPERT_COMMENT` TEXT NULL ,
`FOREIGN_PASSPORT_ID` INT(11) UNSIGNED NULL ,
`SALARY_ID` INT(11) UNSIGNED NULL ,
`SSE_INFO_ID` INT(11) UNSIGNED NULL ,
`EXPERT_NAME` VARCHAR(100) NULL ,
`HR_NAME` VARCHAR(100) NULL ,
`TEACHER_NAME` VARCHAR(100) NULL ,
PRIMARY KEY (`ID`) ,
INDEX `FK_CANDIDATE_ENGLISH_LEVEL1` (`ENGLISH_LEVEL_ID` ASC) ,
INDEX `fk_CANDIDATE_LEVEL1` (`LEVEL_ID` ASC) ,
INDEX `fk_CANDIDATE_FOREIGN_PASSPORT1` (`FOREIGN_PASSPORT_ID` ASC) ,
INDEX `fk_CANDIDATE_SALARY1` (`SALARY_ID` ASC) ,
INDEX `fk_CANDIDATE_SSE_INFO1` (`SSE_INFO_ID` ASC) ,
CONSTRAINT `FK_CANDIDATE_ENGLISH_LEVEL1`
FOREIGN KEY (`ENGLISH_LEVEL_ID` )
REFERENCES `CVM`.`ENGLISH_LEVEL` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_CANDIDATE_LEVEL1`
FOREIGN KEY (`LEVEL_ID` )
REFERENCES `CVM`.`LEVEL` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_CANDIDATE_FOREIGN_PASSPORT1`
FOREIGN KEY (`FOREIGN_PASSPORT_ID` )
REFERENCES `CVM`.`FOREIGN_PASSPORT` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_CANDIDATE_SALARY1`
FOREIGN KEY (`SALARY_ID` )
REFERENCES `CVM`.`SALARY` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_CANDIDATE_SSE_INFO1`
FOREIGN KEY (`SSE_INFO_ID` )
REFERENCES `CVM`.`SSE_INFO` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `CVM`.`CANDIDATE_HISTORY`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `CVM`.`CANDIDATE_HISTORY` (
`ID` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT ,
`CANDIDATE_ID` INT(11) UNSIGNED NOT NULL ,
PRIMARY KEY (`ID`) ,
INDEX `fk_CANDIDATE_HISTORY_CANDIDATE1` (`CANDIDATE_ID` ASC) ,
CONSTRAINT `fk_CANDIDATE_HISTORY_CANDIDATE1`
FOREIGN KEY (`CANDIDATE_ID` )
REFERENCES `CVM`.`CANDIDATE` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `CVM`.`CANDIDATE_CHANGES`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `CVM`.`CANDIDATE_CHANGES` (
`ID` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT ,
`FIELD` VARCHAR(100) NULL ,
`CHANGED_VALUE` TEXT NULL ,
PRIMARY KEY (`ID`) )
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `CVM`.`CANDIDATE_HISTORY_has_CANDIDATE_CHANGES`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `CVM`.`CANDIDATE_HISTORY_has_CANDIDATE_CHANGES` (
`CANDIDATE_HISTORY_ID` INT(11) UNSIGNED NOT NULL ,
`CANDIDATE_CHANGES_ID` INT(11) UNSIGNED NOT NULL ,
PRIMARY KEY (`CANDIDATE_HISTORY_ID`, `CANDIDATE_CHANGES_ID`) ,
INDEX `fk_CANDIDATE_HISTORY_has_CANDIDATE_CHANGES_CANDIDATE_CHANGES1` (`CANDIDATE_CHANGES_ID` ASC) ,
CONSTRAINT `fk_CANDIDATE_HISTORY_has_CANDIDATE_CHANGES_CANDIDATE_HISTORY1`
FOREIGN KEY (`CANDIDATE_HISTORY_ID` )
REFERENCES `CVM`.`CANDIDATE_HISTORY` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_CANDIDATE_HISTORY_has_CANDIDATE_CHANGES_CANDIDATE_CHANGES1`
FOREIGN KEY (`CANDIDATE_CHANGES_ID` )
REFERENCES `CVM`.`CANDIDATE_CHANGES` (`ID` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
在SQL工作台中一切正常,但是使用maven-sql-plugin它无法创建表candidate_history_has_candidate_changes。所有名称都少于64个符号。请帮忙!
答案 0 :(得分:0)
尝试缩小可能的原因,从简单的create table
开始。尝试使用和不使用反引号引用创建这个简单的表,以防插件没有正确处理它们。
检查您是否在两种情况下都以同一用户身份登录。
答案 1 :(得分:0)
查看表中是否有剩余物。如果表已经存在,则CREATE IF NOT EXIST不执行任何操作。 (有关详细信息,请参阅提问者的评论)。
答案 2 :(得分:0)