Question

我昨天问了同样的问题。我在一个好人的帮助下精美地解决了它。

现在，我发现我遗失了一件物品。我想这样做;

1  Boo1    //  "1" is from <sdl:seg id="1">
2  Boo2
3  Boo3
...
..
.

从这里开始。

<xliff xmlns:sdl="http://sdl.com/FileTypes/SdlXliff/1.0">
  <sdl:seg-defs>
      <sdl:seg id="1">
           <sdl:value key="Hash">Foo1</sdl:value>
           <sdl:value key="Created">Boo1</sdl:value>

我试图这样做..

XDocument myDoc = XDocument.Load(myPath);
Dictionary<string, XElement> myDic = myDoc.Descendants()
    .Where(x => x.Name.LocalName == "seg")
    .Select((myValue, myKey) => new { myKey, myValue })
    .ToDictionary(x => x.Attribute("id").Value, x => x);   // Error at .Attribute(  
List<string> myList = myDic
    .Where(x => ((x.Value).Name.LocalName == "value") 
             && ((string)(x.Value).Attribute("key") == "Created"))
    .Select(x.Key + "  " + (string)x.Value);
MessageBox.Show(string.Join("\n", myList));

感谢。

Answer 1

var q = from elem in myDoc.Descendants()
        where elem.Name.LocalName == "seg"
        from sub in elem.Descendants()
        where sub.Name.LocalName == "value" && sub.Attribute("key").Value == "Created"
        select new
        {
            Id = elem.Attribute("id").Value,
            Created = sub.Value
        };

正确的命名空间处理：

XNamespace sdl = "http://sdl.com/FileTypes/SdlXliff/1.0";
var q = from elem in myDoc.Descendants()
        where elem.Name == sdl + "seg"
        from sub in elem.Descendants()
        where sub.Name== sdl + "value" && sub.Attribute("key").Value == "Created"
        select new
        {
            Id = elem.Attribute("id").Value,
            Created = sub.Value
        };

要格式化它：

        var msg = String.Join("\n", q.Select(item => $"{item.Id}   {item.Created}"));

Answer 2

试试这个

            Dictionary<string, List<XElement>> myDic = myDoc.Descendants()  
                .Where(x => x.Name.LocalName == "seg")
                .GroupBy(myKey => (string)myKey.Attribute("id"))
                .ToDictionary(x => x.Key, y => y.Descendants().Where(z => z.Name.LocalName == "value").ToList());

            Dictionary<string, Dictionary<string,string>> myDic2 = myDoc.Descendants()
                 .Where(x => x.Name.LocalName == "seg")
                 .GroupBy(myKey => (string)myKey.Attribute("id"))
                 .ToDictionary(x => x.Key, y => y.Descendants().Where(z => z.Name.LocalName == "value")
                    .GroupBy(z => (string)z.Attribute("key"), a => (string)a)
                    .ToDictionary(z => z.Key, a => a.FirstOrDefault()));

从远处的XDocument解析XElement，重复2次

2 个答案: