Question

我有一个相当复杂的mysqli insert语句要做，因为我需要从其他两个表中收集数据，并且在一个语句中也使用php中可用的一些变量。

由于准备好的陈述的变量顺序，这让我感到困惑。 - 我只插入四个值，但为了获取t1和t2的值，我在bind_param语句中也引用了这三个附加变量。

我应该用$ newJobRoleID，$ newCompanyID，t1.id，t2.id

填充jobRoleID，companyID，departmentID，capabilityID

$addJobCompetencies = $con->prepare("
INSERT INTO jobRoleCompetencies (jobRoleID,companyID,departmentID,competenceID)
WITH t1 AS (SELECT id FROM departments WHERE companyID = ? AND department = ?), 
     t2 AS (SELECT id FROM competencies WHERE companyID = ?)
     SELECT ?,?,t1.id,t2.id FROM t1,t2");

if($addJobCompetencies) {
    $addJobCompetencies->bind_param('isiii', $newCompanyID,$row['department'],$newCompanyID,$newJobRoleID,$newCompanyID);
    $addJobCompetencies->execute();
} else {
    echo $con->error;   
}
$addJobCompetencies->free_result();

我收到语法错误，但我不能100％确定原因。有人可以帮忙吗？

由于丹

Answer 1

我还没有解决这个查询的语法问题，但是通过简单地组合select语句来检索单个select语句中我需要的所有信息......

SELECT？，?, departmentss.id AS departmentID，competencies.id AS competencyID FROM department，competencies ... etc

高级MySQLi查询语法

1 个答案: