Question

将swagger与mvc集成并使用基于java的配置（如

）

@Configuration
@EnableSwagger2
@PropertySource("classpath:application.properties")
public class SwaggerConfig extends WebMvcConfigurerAdapter {
    .
    .
    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("swagger-ui.html").addResourceLocations("classpath:/META-INF/resources/");
        registry.addResourceHandler("/webjars/**").addResourceLocations("classpath:/META-INF/resources/webjars/");
    }
}

并使用网址http://localhost:8080/admin-api/admin/swagger-ui.html，它会给出404。当我从addResourceHandlers配置类中删除SwaggerConfig并通过xml配置

时

<mvc:resources mapping="swagger-ui.html" location="classpath:/META-INF/resources/" />
<mvc:resources mapping="/webjars/**" location="classpath:/META-INF/resources/webjars/" />

使用相同的网址http://localhost:8080/admin-api/admin/swagger-ui.html，它运行没有问题。我该如何使用基于java的配置？

Answer 1

swagger - 基于java的配置一个类来自WebMvcConfigurerAdapter，在该类文件中通过覆盖 addResourceHandlers ，如下所示

@Configuration
public class AppConfig extends WebMvcConfigurerAdapter {
   @Override
   public void addResourceHandlers(ResourceHandlerRegistry registry) {
    registry.addResourceHandler("swagger-ui.html").addResourceLocations("classpath:/META-INF/resources/");
    registry.addResourceHandler("/webjars/**").addResourceLocations("classpath:/META-INF/resources/webjars/");
    super.addResourceHandlers(registry);
   }
}

Answer 2

尝试使用@EnableWebMvc举报SwaggerConfig并将"**/**"注册为另一个ResourceHandler，如下所示：

@Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
    registry.addResourceHandler("**/**").addResourceLocations("classpath:/META-INF/resources/");
    registry.addResourceHandler("/webjars/**").addResourceLocations("classpath:/META-INF/resources/webjars/");
}

另请参阅Docket，这是使用Docket API的示例应用程序的链接 - swagger-example。

Swagger和Spring MVC集成

2 个答案: