我使用后台工作程序创建了一个c#项目。它包含一个“开始”按钮,用于启动后台工作程序。这是我的代码。
using System.Threading.Tasks;
using System.Windows;
namespace Test
{
public partial class MainWindow : Window
{
int status = 0;
private void btnstart_Click(object sender, RoutedEventArgs e)
{
worker.DoWork += worker_DoWork;
worker.RunWorkerCompleted += worker_RunWorkerCompleted;
worker.RunWorkerAsync();
Console.WriteLine("Background worker started successfully");
btnsave.IsEnabled = false;
}
private void worker_DoWork(object sender, DoWorkEventArgs e)
{
if (worker.CancellationPending)
{
e.Cancel = true;
return;
}
Console.WriteLine("Status : " + status);
if (status == 0)
{
status = 1;
}
}
private void worker_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
Console.WriteLine("worker completed");
btnsave.IsEnabled = true;
}
}
}
但每次,我点击开始按钮,我得到这样的输出
attempt 1.
Status : 0
The thread 0x23dc has exited with code 0 (0x0).
Status : 1
attempt 2.
Status : 0
The thread 0x148 has exited with code 0 (0x0).
Status : 1
Status : 1
attempt 3.
Status : 0
The thread 0x128 has exited with code 0 (0x0).
Status : 1
Status : 1
Status : 1
我只在现有工人完成后启动后台工作程序。那么为什么“状态”日志会像这样打印出来。
答案 0 :(得分:7)
问题是由事件处理程序分配产生的:
using System.Threading.Tasks;
using System.Windows;
namespace Test
{
public partial class MainWindow : Window
{
int status = 0;
// should be called when the window is loaded
private void ApplicationStart()
{
worker.DoWork += worker_DoWork;
worker.RunWorkerCompleted += worker_RunWorkerCompleted;
}
private void btnstart_Click(object sender, RoutedEventArgs e)
{
worker.RunWorkerAsync();
Console.WriteLine("Background worker started successfully");
btnsave.IsEnabled = false;
}
private void worker_DoWork(object sender, DoWorkEventArgs e)
{
if (worker.CancellationPending)
{
e.Cancel = true;
return;
}
Console.WriteLine("Status : " + status);
if (status == 0)
{
status = 1;
}
}
private void worker_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
Console.WriteLine("worker completed");
btnsave.IsEnabled = true;
}
}
}
每次单击按钮都会执行此操作。由于它是a + =你多次分配它。
只需在窗口初始化中添加事件处理程序:
{{1}}