每个类别,子类别和标准都有3个主集合,我将构建框架,其中包含类别,子类别和标准的任何可能组合,这些组合将存储如下 -
框架文档下面添加了标准列表作为嵌入对象,进一步具有类别,子类别和标准的单个对象。你可以将criteriaconfig称为你在mysql中调用的链接表。
[
{
"id": "592bc3059f3ad715002b2331",
"name": "Framework1",
"description": "framework 1 for testing",
"criteriaConfigs": [
{
"id": "592bc3059f3ad715002b232f",
"category": {
"id": "591c2f5faa187956b2d0fb39",
"name": "category1",
"description": "category1",
"deleted": false,
"createdDate": 1495019359558
},
"subCategory": {
"id": "591c2f5faa187956b2d0fb83",
"name": "subCat1",
"description": "subCat1"
},
"criteria": {
"id": "591c2f5faa187956b2d0fbad",
"name": "criteria1",
"measure": "Action"
}
},
{
"id": "592bc3059f3ad715002b232e",
"category": {
"id": "591c2f5faa187956b2d0fb37",
"name": "Process",
"description": "Enagagement"
},
"subCategory": {
"id": "591c2f5faa187956b2d0fb81",
"name": "COMM / BRANDING",
"description": "COMM / BRANDING"
},
"criteria": {
"id": "591c2f5faa187956b2d0fba9",
"name": "Company representative forgets about customer on hold",
"measure": ""
}
} ]
},
{
"id": "592bc3059f3ad715002b2332",
"name": "Framework2",
"description": "framework 2 for testing",
"criteriaConfigs": [
{
"id": "592bc3059f3ad715002b232f",
"category": {
"id": "591c2f5faa187956b2d0fb39",
"name": "category1",
"description": "category1"
},
"subCategory": {
"id": "591c2f5faa187956b2d0fb83",
"name": "subCat1",
"description": "subCat1"
},
"criteria": {
"id": "591c2f5faa187956b2d0fbad",
"name": "criteria1",
"measure": "Action"
}
}
]
}
]
我需要一个包含框架的视图,该框架将包含所有类别列表和内部类别,将有添加的子类别列表,内部子类别将包含单个框架的标准列表。
预期结果 -
[
{
"id": "f1",
"name": "Framework1",
"description": "framework 1 for testing",
"categories": [
{
"id": "c2",
"name": "category2",
"description": "category2",
"subCategories": [
{
"id": "sb1",
"name": "subCat1",
"description": "subCat1",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr2",
"name": "criteria2",
"measure": "Action"
},
{
"id": "cr3",
"name": "criteria3",
"measure": "Action"
}]
},
{
"id": "sb2",
"name": "subCat2",
"description": "subCat2",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr4",
"name": "criteria4",
"measure": "Action"
}]
}]
},
{
"id": "c1",
"name": "category1",
"description": "category1",
"subCategories": [
{
"id": "sb3",
"name": "subCat3",
"description": "subCat3",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr2",
"name": "criteria2",
"measure": "Action"
}
]},
{
"id": "sb2",
"name": "subCat2",
"description": "subCat2",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr4",
"name": "criteria4",
"measure": "Action"
}]
}
]
}]
},
{
"id": "f2",
"name": "Framework2",
"description": "framework 2 for testing",
"categories": [
{
"id": "c2",
"name": "category2",
"description": "category2",
"subCategories": [
{
"id": "sb4",
"name": "subCat5",
"description": "subCat5",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr3",
"name": "criteria3",
"measure": "Action"
}]
},
{
"id": "sb2",
"name": "subCat2",
"description": "subCat2",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr4",
"name": "criteria4",
"measure": "Action"
}]
}]
},
{
"id": "c1",
"name": "category1",
"description": "category1",
"subCategories": [
{
"id": "sb3",
"name": "subCat3",
"description": "subCat3",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr2",
"name": "criteria2",
"measure": "Action"
}
]},
{
"id": "sb2",
"name": "subCat2",
"description": "subCat2",
"criterias": [
{
"id": "cr1",
"name": "criteria1",
"measure": "Action"
},
{
"id": "cr4",
"name": "criteria4",
"measure": "Action"
}]
}
]
}]
}
]
注意 - 类别文档没有对子类别的任何引用,并且子类别目前没有对条件对象的任何引用,因为它们是主数据并且是通用的,框架是动态创建的。
答案 0 :(得分:0)
如果您想尝试在聚合中完成所有工作,可以先按子类别分组,然后按类别分组:
db.collection.aggregate([
{$unwind:"$criteriaConfigs"},
{$project:{
_id:0,
category:"$criteriaConfigs.category",
subCategory:"$criteriaConfigs.subCategory",
criteria:"$criteriaConfigs.criteria"
}},
{$group:{
_id:{"category":"$category","subCategory":"$subCategory"},
criteria:{$addToSet:"$criteria"}
}},
{$group:{
_id:{"category":"$_id.category"},
subCategories:{$addToSet:{subCategory:"$_id.subCategory",
criteria:"$criteria"}}
}},
{$project:{
_id:0,category:"$_id.category",
subCategories:"$subCategories"
}}
])
根据您计划返回数据的方式,返回每个唯一组合可能更有效:
db.collection.aggregate([
{$unwind:"$criteriaConfigs"},
{$group:{
_id:{
category:"$criteriaConfigs.category.name",
subCategory:"$criteriaConfigs.subCategory.name",
criteria:"$criteriaConfigs.criteria.name"
}
}},
{$project:{
_id:0,
category:"$_id.category",
subCategory:"$_id.subCategory",
criteria:"$_id.criteria"
}}
])
我不确定你的问题是什么形状你期望返回数据,所以你可能需要调整它。