Question

我能够使用以下PSQL查询（最后）来获取表格中单行的dense_rank，但是，我希望能够将其显示为：< / p>

dense_rank OUT OF total distinct ranks

例如，由于dense_rank允许“联系”，可以这么说，如果我有100行并且所选行排名第14（并且只有59个不同的排名），我我想说：

Ranked 14th out of 59

有没有办法可以修改我的查询来实现这个目标，还是我必须使用多个查询？

这是我的问题：

SELECT ranked.*
FROM
  (SELECT id,
          postable_id,
          spread_count,
          bury_count,
          read_count,
          (spread_count*3) + (bury_count*-2) + (read_count*-1) AS score,
          dense_rank() OVER (
                             ORDER BY (spread_count*3) + (bury_count*-2) + (read_count*-1) DESC) AS RANK
   FROM posts) AS ranked
WHERE id = ?

Answer 1

你可以试试这个。

SELECT t.*
FROM (SELECT ranked.*, 
      RNK||' out of '||MAX(RNK) OVER() as rnk_pos
      FROM
       (SELECT id,
          postable_id,
          spread_count,
          bury_count,
          read_count,
          (spread_count*3) + (bury_count*-2) + (read_count*-1) AS score,
          dense_rank() OVER (
                             ORDER BY (spread_count*3) + (bury_count*-2) + (read_count*-1) DESC) AS RNK
        FROM posts) AS ranked
      ) t
WHERE id=?

Answer 2

基本上，你想要这个：

\r\n

唉，这不起作用，因为Postgres不支持Dim rs As New ADODB.Recordset Dim strSQL As String strSQL = "DELETE FROM mytable WHERE mycol>5;" ConnectDB rs.Open strSQL, ConnDB作为窗口函数。您可以使用其他窗口函数实现它：\

SELECT p.*
FROM (SELECT p.*
             (spread_count*3) + (bury_count*-2) + (read_count*-1) AS score,
             dense_rank() OVER (ORDER BY (spread_count*3) + (bury_count*-2) + (read_count*-1) DESC) AS RANK,
             count(distinct (spread_count*3) + (bury_count*-2) + (read_count*-1)) over () as outof
      FROM posts p
     ) p
WHERE id = ?;

PSQL dense_rank中不同总项目中的一项

2 个答案: