Question

我在两个不同的查询中从表中提取数据，我正在尝试比较两个结果中的日期字段。当日期相等时，我想将每个查询的两个结束余额加在一起，并将结果放入一个新数组中。我遇到的问题是on line 59，我得到的错误是 Notice: Undefined offset。

这就是我所拥有的：

 include "../sqlConnect.php";

 mysqli_set_charset($dbScrap, 'utf8');
 $dataArray[] = array();
$dateArray[] = array();
$balanceArray[] = array();

//Smaller
$query = "SELECT Account, Date ,SUM(EndingBalance) AS 'Month_Total' FROM gl_period_posting_history
    INNER JOIN gl_account
      ON gl_period_posting_history.AccountKey = gl_account.AccountKey
  Where gl_account.Account= '5010-15-0000' AND  FiscalYear > 2012
  GROUP BY Account, Date";

$result = mysqli_query( $dbScrap, $query) or die("SQL Error 1: " . 
mysqli_error($dbScrap));
while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)){

$EndingBalance15 = $row['Month_Total'];
$Date15 = $row['Date'];

$dateArray[] = array(
    'Date' => $Date15
);

$balanceArray[] = array(
    'EndingBalance' => $EndingBalance15
);


}


\\Bigger
    $query1 = "SELECT Account, Date ,SUM(EndingBalance) AS 'Month_Total' FROM gl_period_posting_history
    INNER JOIN gl_account
      ON gl_period_posting_history.AccountKey = gl_account.AccountKey
  Where gl_account.Account ='5010-08-0000' AND  FiscalYear > 2012
  GROUP BY Account, Date";

 $result = mysqli_query( $dbScrap,$query1) or die("SQL Error 1: " . mysqli_error($dbScrap));
 while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)){

$Date08 = $row['Date'];
$EndingBalance08 = $row['Month_Total'];

for($i = 0; $i < $dateArray; $i++){
        if($Date08 == $dateArray[$i]) {
            $message = "Date Equal";
            $EndingBalance = $EndingBalance08 + $balanceArray[$i];
            $Date = $Date08;
        }else{
            $message = "Date Not Equal";
            $Date = $Date08;
            $EndingBalance = $EndingBalance08;
        }
    }
    $dataArray[] = array(

        'EndingBalance' => $EndingBalance,
        'Date' => $Date,
        'Message' => $message
    );
 }
 echo "<pre>";
 print_r($dataArray);
 //echo json_encode($dataArray);
 echo "</pre>";

 $result->close();
 /* close connection */
 $dbScrap->close();

感谢您的帮助。

Answer 1

问题在于循环，纠正：

for ($i = 0; $i < count($dateArray); $i++){

Answer 2

在您从第一个查询中获取结果的循环中，使用每行中的日期作为$balanceArray中的键，如下所示：

while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)) {
    $EndingBalance15 = $row['Month_Total'];
    $Date15 = $row['Date'];

    $balanceArray[$Date15] = $EndingBalance15;
}

然后在从第二个查询中获取结果的循环中，您可以使用isset检查第一个查询的结果中是否存在该日期，如下所示。

while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)) {

    $Date08 = $row['Date'];
    $EndingBalance08 = $row['Month_Total'];

    if (isset($balanceArray[$Date08])) {
        $message = "Date Equal";
        $EndingBalance = $EndingBalance08 + $balanceArray[$Date08];
    } else {
        $message = "Date Not Equal";
        $EndingBalance = $EndingBalance08;
    }
    $dataArray[] = array(
        'EndingBalance' => $EndingBalance,
        'Date' => $Date08,
        'Message' => $message
    );
}

从其他数组创建数组

2 个答案: