现在我尝试编写一个C#程序,将8 Base Binary翻译成Text。
但我想我对C#的经验不足以让它真正发挥作用。
我认为我提出的代码应该从逻辑的Point-of-View中做出我想要的,但语法没有正确地执行它,因为不要更好地了解它。
这是我到目前为止所做的:
using System;
using System.Linq;
using System.Text;
class binaryTranslate
{
public int convertBin(string CodeInput)
{
int [] code = CodeInput.ToArray();
int CodeCount = code.ToString().Length;
int EightBaseSegAmount = CodeCount / 8;
int ByteCapacity = 8;
StringBuilder translated = new StringBuilder();
for (var i = 1; i < EightBaseSegAmount + 1; i++)
{
StringBuilder Byte = new StringBuilder(ByteCapacity);
int ByteStart = (i * 8) - 8;
int ByteEnd = (i * 8) - 1;
int ByteIncrement = 1;
for (var j = ByteStart ; j < ByteEnd + 1; j++)
{
Byte.Append(code[j]);
}
for (var k = 0; k > 7; k++)
{
int BitValue = 128;
if (Byte[k] == 1)
{
if (k > 0)
{
int Squared = Math.Pow(2, k);
ByteIncrement += BitValue / Squared;
}
else
{
ByteIncrement += BitValue;
}
}
}
char toSymbol = Convert.ToChar(ByteIncrement);
translated.Append(toSymbol);
}
return translated;
}
public static int Main()
{
convertBin("010010000110000101101100011011000110111100100001");
}
}
答案 0 :(得分:2)
首先,您的代码无法编译。这是错误/错误。
String.ToArray()
将输入字符串转换为数组,返回char[]
,但您尝试将其分配给变量(代码)输入int[]
。您可以将int[]
替换为char[]
或var
来解决此问题。(k = 0; k > 7)
内,您使用Math.Pow()
并将其返回值分配给int
变量(Squared)。但Math.Pow
返回加倍。您可以通过将Math.Pow
的返回值转换为int
来解决此问题。喜欢; int Squared = (int)Math.Pow(2, k);
translated
的内容,该内容是StringBuilder
类型的变量。但是您的函数被定义为返回int
。现在这些都是编译错误。存在许多逻辑和决策错误/错误。你的算法也不是很正确。
以下是您可以使用/检查的示例代码。我想进一步帮助您,为什么您的代码不正确,您的设计错误是什么等等。
class binaryTranslate
{
public enum IncompleteSegmentBehavior
{
Skip = 0,
ZerosToStart = 1,
ZerosToEnd = 2
}
private byte ConvertBinstrToByte(string sequence)
{
if (string.IsNullOrEmpty(sequence))
return 0; // Throw?
if (sequence.Length != sizeof(byte) * 8)
return 0; // Throw?
const char zero = '0';
const char one = '1';
byte value = 0;
for (int i = 0; i < sequence.Length; i++)
{
if (sequence[i] != zero && sequence[i] != one)
return 0; // Throw
value |= (byte)((sequence[i] - zero) << (7 - i));
}
return value;
}
private string HandleIncompleteSegment(string segment, int segmentSize, IncompleteSegmentBehavior behavior)
{
string result = null;
var zeroAppender = new StringBuilder();
for (int i = 0; i < segmentSize - segment.Length; i++)
zeroAppender.Append('0');
var zeros = zeroAppender.ToString();
switch (behavior)
{
case IncompleteSegmentBehavior.Skip:
break;
case IncompleteSegmentBehavior.ZerosToStart:
result = zeros + result;
break;
case IncompleteSegmentBehavior.ZerosToEnd:
result = result + zeros;
break;
default:
break;
}
return result;
}
public byte[] ConvertBinstrToBytes(string binarySequence, IncompleteSegmentBehavior behavior = IncompleteSegmentBehavior.Skip)
{
var segmentSize = sizeof(byte) * 8;
var sequenceLength = binarySequence.Length;
var numberOfBytes = (int)Math.Ceiling((double)sequenceLength / segmentSize);
var bytes = new byte[numberOfBytes];
for (int i = 0; i < numberOfBytes; i++)
{
var charactersLeft = sequenceLength - i * segmentSize;
var segmentLength = (charactersLeft < segmentSize ? charactersLeft : segmentSize);
var segment = binarySequence.Substring(i * segmentSize, segmentLength);
if (charactersLeft < segmentSize)
{
segment = HandleIncompleteSegment(segment, segmentSize, behavior);
if (segment == null)
continue;
}
bytes[i] = ConvertBinstrToByte(segment);
}
return bytes;
}
}
此代码传递了这些断言。
var bytes = new binaryTranslate()
.ConvertBinstrToBytes("00000000");
Assert.Equal(bytes.Length, 1);
Assert.Equal(bytes[0], 0b00000000);
bytes = new binaryTranslate()
.ConvertBinstrToBytes("10000000");
Assert.Equal(bytes.Length, 1);
Assert.Equal(bytes[0], 0b10000000);
bytes = new binaryTranslate()
.ConvertBinstrToBytes("11111111");
Assert.Equal(bytes.Length, 1);
Assert.Equal(bytes[0], 0b11111111);
bytes = new binaryTranslate()
.ConvertBinstrToBytes("00000001");
Assert.Equal(bytes.Length, 1);
Assert.Equal(bytes[0], 0b00000001);
bytes = new binaryTranslate()
.ConvertBinstrToBytes("1100110000110011");
Assert.Equal(bytes.Length, 2);
Assert.Equal(bytes[0], 0b11001100);
Assert.Equal(bytes[1], 0b00110011);
答案 1 :(得分:0)
如果您真的转换为字符串,则代码应如下所示
namespace binaryTranslate
{
class Program
{
static void Main(string[] args)
{
//convertBin("01001000 01100001 01101100 01101100 01101111 00100001");
string results = BinaryTranslate.convertBin(new byte[] { 0x44, 0x61, 0x6c, 0x6c, 0x6f, 0x21 });
}
}
public class BinaryTranslate
{
public static string convertBin(byte[] CodeInput)
{
return string.Join("", CodeInput.Select(x => x.ToString("X2")));
}
}
}
答案 2 :(得分:0)
这应该可以解决问题。
public static string FromBinary(string binary)
{
int WordLength = 8;
binary = binary.Replace(' ', '');
while(binary.Length % WordLength != 0)
binary += "0";
string output = String.Empty;
string word = String.Empty;
int offset = 0;
while(offset < binary.Length)
{
int tmp = 0;
word = binary.Substring(offset, 8);
for(int i=0; i<(WordLength - 1); i++)
if(word[i] == '1')
tmp += (int) Math.Pow(2, i);
output += Convert.ToChar(tmp);
offset += WordLength;
}
return output;
}