Question

我是java的新手，我对解析的JSON数据有一点问题，下面你可以看到我的代码，我将JSON数据解析为ListView，你可以在我的代码中看到，现在我想添加点击ListView中每个项目的监听器，当用户点击他想要的项目时，应打开所选项目的URL链接，我尝试通过意图，但我不知道如何更新来自JSON的 uri 字段，提前感谢。

protected void onPostExecute(Void result) {
  super.onPostExecute(result);
  // Dismiss the progress dialog
  if (pDialog.isShowing())
      pDialog.dismiss();

  /**
   * Updating parsed JSON data into ListView
   * */
  ListAdapter adapter = new SimpleAdapter(
          MainActivity.this, contactList,
          R.layout.list_item, new String[]{"name", "email",
          "mobile"}, new int[]{R.id.name,
          R.id.email, R.id.mobile});

  lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
      public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
          String url = "email";
          Intent i = new Intent(Intent.ACTION_VIEW);
          i.setData(Uri.parse(url));
          startActivity(i);
      }
  });

  lv.setAdapter(adapter);
}


{
    "contacts": [
        {
                "id": "c200",
                "name": "Ravi Tamada",
                "email": "",
                "address": "xx-xx-xxxx,x - street, x - country",
                "gender" : "male",
                "phone": {
                    "mobile": "+91 0000000000",
                    "home": "00 000000",
                    "office": "00 000000"
                }
        },
        {
                "id": "c201",
                "name": "senjo",
                "address": "xx-xx-xxxx,x - street, x - country",
                "gender" : "male",
                "phone": {
                    "mobile": "+91 0000000000",
                    "home": "00 000000",
                    "office": "00 000000"
                }
        },
        {
                "id": "c202",
                "name": "Leonardo Dicaprio",
                "email": "leonardo_dicaprio@gmail.com",
                "address": "xx-xx-xxxx,x - street, x - country",
                "gender" : "male",
                "phone": {
                    "mobile": "+91 0000000000",
                    "home": "00 000000",
                    "office": "00 000000"
                }
        },
        {
                "id": "c203",
                "name": "John Wayne",
                "email": "john_wayne@gmail.com",
                "address": "xx-xx-xxxx,x - street, x - country",
                "gender" : "male",
                "phone": {
                    "mobile": "+91 0000000000",
                    "home": "00 000000",
                    "office": "00 000000"
                }

Answer 1

要打开您应该尝试的网址

String url = "http://www.example.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);

Answer 2

以下是您将如何做到这一点：

ListAdapter adapter = new SimpleAdapter(
MainActivity.this, contactList,
R.layout.list_item, new String[]{"name", "email", "mobile"}, 
    new int[]{R.id.name, R.id.email, R.id.mobile});

lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        String url = contactList.get(position).get("url");
        Intent i = new Intent(Intent.ACTION_VIEW);
        i.setData(Uri.parse(url));
        startActivity(i);
    }
});

lv.setAdapter(adapter);

编辑：好的，在您的编辑中，您的JSON中实际上没有url字段。如果您要打开的url实际上是电子邮件地址，那么您必须使用此代码：

lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        String email = contactList.get(position).get("email");
        if (email != null && !email.isEmpty()) {
            Intent i = new Intent(Intent.ACTION_SENDTO);
            i.setData(Uri.parse("mailto:" + email));
            startActivity(i);
        }
    }
});

使用json值管理java

2 个答案: