Question

我有一个名为agent_payment的表，其中包含架构。

Schema::create('agent_payment', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('agent_id');
        $table->integer('created_by');
        $table->integer('rid')->nullable()->comment('Only For Admin Reservation');
        $table->string('date');
        $table->string('paid_amount');
        $table->string('paid_by')->nullable();
        $table->string('received_by')->nullable();
        $table->enum('type',['cash','cheque']);
        $table->string('bank_name')->nullable();
        $table->string('cheque_num')->nullable();
        $table->string('deposited_to')->nullable();
        $table->string('account_num')->nullable();
        $table->string('slip')->nullable();
        $table->integer('verified')->default(0)->comment('Verified 1 Unverified 0');
        $table->integer('status_change')->default(0);
        $table->string('reject_message')->nullable();
        $table->timestamps();
    });

我有此表AgentPayment的模型。

现在，我正在尝试在两列中获取具有相同值的记录。

我只需要

记录

status_change = 0且已验证= 0

或

status_change = 1且已验证= 1

很容易得到上述任何一个：

$payments = AgentPayment::where('status_change',1)->where('verified',1)->get();

但是如何获得这两者。

Answer 1

如果你想要实现几个分组，那么你可以使用这样的闭包来做到这一点：

AgentPayment::where(function($query) {
    return $query->where('status_change', 1)->where('verified', 1);
})->orWhere(function($query) {
    return $query->where('status_change', 0)->where('verified', 0);
})->get();

这应该导致查询看起来像：

select * from agent_payment where (status_change = 1 AND verified = 1) OR (status_change = 0 AND verified = 0)

Answer 2

我认为这样的事情会给你答案：

$payments = AgentPayment::where(['status_change', 1],['verified', 1])->orWhere(['verified',0], ['status_change', 0])->get();

如何从具有两列的表中获取记录具有相同的值？

2 个答案: