Question

我将JSON object格式化为

{ 
   id: 'a60c09fa-9b60-4b14-9ee6-41d64d243435',
   contactData: {
      phone: '526 669 77',
      email: 'client@test.ee',
      skype: 'skype',
      company_name: 'CLIent22',
      address: 'address',
      contact_person: 'Person'
   }
}

我想将其转换为

{ 
       id: 'a60c09fa-9b60-4b14-9ee6-41d64d243435',
       phone: '526 669 77',
       email: 'client@test.ee',
       skype: 'skype',
       company_name: 'CLIent22',
       address: 'address',
       contact_person: 'Person'
    }

如何做到这一点。寻找你的帮助和建议。

Answer 1

ES6中的

：

let result = {
  id: input.id,
  ...input.contactData
}

或使用jQuery：

var result = $.extend({ id: input.id }, input.contactData);

Answer 2

怎么样？

var yourobject ={ 
   id: 'a60c09fa-9b60-4b14-9ee6-41d64d243435',
   contactData: {
      phone: '526 669 77',
      email: 'client@test.ee',
      skype: 'skype',
      company_name: 'CLIent22',
      address: 'address',
      contact_person: 'Person'
   }
}
var newObject=yourobject.contactData;
newObject.id=yourobject.id;

Answer 3

您可以使用Object.create生成对象的副本，而不会改变原始对象。然后添加其他属性。

var original = { id: 'a60c09fa-9b60-4b14-9ee6-41d64d243435', contactData: { phone: '526 669 77', email: 'client@test.ee', skype: 'skype', company_name: 'CLIent22', address: 'address', contact_person: 'Person' } },
    result = Object.create(original.contactData);

result.id = original.id;
console.log(result);
console.log(original);

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JSON对象转换

3 个答案: