Question

如何匹配文字

$line = "study of 557 adults suffering from sleep";

来自

 $content = "The International Journal of Nursing published a
<b>study of 557 adults suffering</b>
<br>
<b>from sleep</b>
disorders. In this study, music was played when they ...";

并且内容可以是

 $content = "The International Journal of Nursing published a
<b>study of 557 adults suffering from sleep</b>
disorders. In this study, music was played when they ...";

所以我需要一个适用于两者的解决方案

preg_match("#<b>$line</b>#is",$content,$match);

Answer 1

喜欢这个？ https://regex101.com/r/PDehGB/2

$pattern = '/<b>study.*?of.*?557.*?adults.*?suffering.*?from.*?sleep<\/b>/ms';

使用这种模式，它将处理任何新行并仍然保持$ line。

你可以爆炸＆＃34;上的$ line; ＆＃34;并使用implode(".*?", $arr)

构建模式

Answer 2

您可以使用此正则表达式（https://regex101.com/r/elRsha/2）：

$line = "study of 557 adults suffering from sleep";

$content = "The International Journal of Nursing published a
<b>study of 557 adults suffering</b>
<br>
<b>from sleep</b>
disorders. In this study, music was played when they ...";

$line = implode('(?:[\n\s\t]*(?:<.+>)*[\n\s\t]*)*', explode(' ', $line));

preg_match("#($line)#is",$content,$match);
print_r($match);

Answer 3

首先使用strip_tags函数从字符串中删除HTML标记，然后从字符串中删除换行符。

$line = "study of 557 adults suffering from sleep";

$content = "The International Journal of Nursing published a
<b>study of 557 adults suffering</b>
<br>
<b>from sleep</b>
disorders. In this study, music was played when they ...";

echo preg_match("#$line#is",trim(preg_replace('/\s+/', ' ', strip_tags($content))),$match);

PHP preg_match匹配相同标签的多个出现之间的文本

3 个答案: