使用我使用的新代码。我试过这个,如果我先声明了,那就行了,这不是我想要的。我需要知道总行数 (n)并在我的模拟中使用该数字。但是,在变量声明中,我需要在读取数据之前减少我的xy(n),如果我这样做,则代码不会运行。
数据文件是两列随机模拟的普通数据
让我们这样说
1 3
2 4
3 6
4 8
5 9
6 8
7 1
8 9
99 88
我尝试了以下代码来确定n,但它没有用!
program reading
implicit none
integer,allocatable :: a(:,:)
integer :: pair(2)
integer :: unit, n, io,k
!!!variable declaration
real, dimension(1:n)::x,y
integer:: T, I1, I2, I3, i, j, dist
open(2, file = 'xyBVNData_R.txt', status = 'old', action = 'read')
n = 0
DO
READ(2,*,iostat=io)
IF (io/=0) EXIT
n = n + 1
END DO
CLOSE (2)
print*, n
DO i=1,n!!!
DO j=1,n!!
dist=0.0
DIST = dist+(sqrt((x(i)-x(j))**2 + (y(i)-y(j))**2))
ENDDO
ENDDO
!!! writing and saving
Do i= 1, n
write(*,*) i, x(i)
ENDDO
end program reading
答案 0 :(得分:3)
您不能声明具有未知维度“dimension(1:n)”的变量。
program reading
implicit none
! variable declaration
real, dimension(:) ,allocatable :: x ,y
real :: dist
integer:: i, j ,n ,io
open(2, file = 'xyBVNData_R.txt', status = 'old', action = 'read')
n = 0
DO
READ(2,*,iostat=io)
IF (io/=0) EXIT
n = n + 1
END DO
print*, n
allocate( x(n) ,y(n) )
rewind(2)
DO i =1,n
READ(2,*) x(i),y(i)
END DO
dist=0.0
DO i=1,n
DO j=1,n
dist = dist + sqrt( (x(i)-x(j))**2 + (y(i)-y(j))**2 )
END DO
END DO
! writing and saving
DO i= 1, n
write(*,*) i, x(i)
END DO
end program reading
另一种选择(Fortran 2003)
program reading
implicit none
! variable declaration
real, dimension(:) ,allocatable :: x ,y
real :: dist ,x_tmp ,y_tmp
integer:: i, j ,n ,io
open(2, file = 'xyBVNData_R.txt', status = 'old', action = 'read')
n = 0
allocate( x(0) ,y(0) )
DO
READ(2,*,iostat=io) x_tmp,y_tmp
x = [x,x_tmp]
y = [y,y_tmp]
IF (io/=0) EXIT
n = n + 1
END DO
print*, n
dist=0.0
DO i=1,n
DO j=1,n
dist = dist + sqrt( (x(i)-x(j))**2 + (y(i)-y(j))**2 )
END DO
END DO
! writing and saving
DO i= 1, n
write(*,*) i, x(i)
END DO
end program reading