如何通过AngularJS $资源检索外部资源(JSON)

时间:2017-05-30 07:11:44

标签: angularjs

我正在尝试从openweathermap.org(JSON)中检索天气数据,

这是我的控制器代码:

weatherApp.controller('forecastController', ['$scope', '$log', 'forecastService', function($scope, $log, forecastService) {

    $log.info(forecastService.getWeather('Davao City', '5'));

}]);

这是我的服务代码:

weatherApp.service('forecastService', [ '$resource', '$sce', function 
 ($resource, $sce) {

    this.getWeather = function (city, numDays){

        var key = 'b3cc85931eae059522f3a9b8c5260f6e';

        var link = function() {
           return $sce.trustAsResourceUrl("http://api.openweathermap.org/data/2.5/forecast/");
        };

        var weatherAPI = $resource(link(), { callback: "JSON_CALLBACK" }, { get: { method: "JSONP" }});

        var weatherResult = weatherAPI.get({ q: city, cnt: numDays, appid: key });

        return weatherResult;
    };

}]);

Kept on getting this error, please help T_T

angular.min.js:123 TypeError: c.split is not a function
    at C.setUrlParams (http://127.0.0.1:50003/core-js/angular-resource.min.js:12:269)
    at Function.l.(anonymous function) [as get] (http://127.0.0.1:50003/core-js/angular-resource.min.js:10:156)
    at Object.getWeather (http://127.0.0.1:50003/project-js/forecast.factory.js:14:40)
    at new <anonymous> (http://127.0.0.1:50003/project-js/forecast.controller.js:3:31)
    at Object.instantiate (http://127.0.0.1:50003/core-js/angular.min.js:44:272)
    at http://127.0.0.1:50003/core-js/angular.min.js:94:141
    at Object.link (http://127.0.0.1:50003/core-js/angular-route.min.js:7:322)
    at http://127.0.0.1:50003/core-js/angular.min.js:17:3
    at ra (http://127.0.0.1:50003/core-js/angular.min.js:85:35)
    at n (http://127.0.0.1:50003/core-js/angular.min.js:70:226) "<div ng-view="" class="ng-scope">"

1 个答案:

答案 0 :(得分:0)

在您的情况下,weatherResult变量是一个promise对象。您可以通过以下方式获取控制器中的$ http调用返回值:

  myPromiseReturningServiceFunctionCall.$promise(successFunction(data) {
          // Do something with the data.
      }, errorFunction(error) {
      }
   )

所以在你的情况下代码应该是:

forecastService.getWeather('Davao City', '5').$promise(
      successFunction(data) {
          // Do something with the data.
      }, errorFunction(error) {
      })

有关$ resource的更多信息,您可以随时参考docs。返回部分将为您提供更多信息。