Question

我想在字符串中获取一个项目

主要字符串是：ABX16059636/903213712,

我想提取Regex有没有办法使用{{1}}来实现这个？

请与我们分享一些建议。

Answer 1

尝试使用以下正则表达式，

＆＃13;

var string = "This is an inactive AAA product. It will be replaced by replacement AAAA/BBBB number ABX16059636/903213712 during quoting"

var result = string.match(/[A-Z]+[0-9]+\/[0-9]+/g)

console.log(result)

＆＃13;

Answer 2

var s = 'This is an inactive AAA product. It will be replaced by replacement AAAA/BBBB number ABX16059636/903213712 during quoting'
var pat = /[A-Z]{3}\d+\/\d+/i
pat.exec(s)

此正则表达式匹配任意3个字母，后跟一个或多个数字，后跟/，然后是一个或多个数字。

Answer 3

尝试下面的代码。它会显示您的匹配项以及匹配组。

＆＃13;

const regex = /[A-Z]+[0-9]+\/+[0-9]+/g;
const str = `This is an inactive AAA product. It will be replaced by replacement AAAA/BBBB number ABX16059636/903213712 during quoting`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

＆＃13;

Live Demo

Answer 4

我去了https://regex101.com/r/ARkGkz/1
我为你写了一个正则表达式
我使用他们的代码生成器来生成Javascript代码
然后，我将Javascript代码修改为仅访问您之后的单个匹配

结果如下：

const regex = /number ([^ ]+) /;
const str = `This is an inactive AAA product. It will be replaced by 
replacement AAAA/BBBB number ABX16059636/903213712 during quoting`;
let m;

if ((m = regex.exec(str)) !== null) {
    let match = m[1];
    console.log(`Found match: ${match}`);
}

正则表达式本身可以理解为：

第一场比赛number
括号中包含我们要捕获的部分
[^ ]表示“除空格字符外的任何内容”
+表示“其中一项或多项”
然后在最后，我们匹配一个尾随空格

请使用https://regex101.com/r/ARkGkz/1并进行试验。

如何使用Regex获取字符串中的字母数字或数字值？

4 个答案: