Question

在编写代码以将我的mysql的结果回显到我的数据库表之后，现在我正在尝试将所选行放在我的更新页面上，就像从表中显示一些信息一样，并且能够更新该表同时

我对我在其他地方实际阅读的所有在线帮助感到困惑，但我相信我写了正确的代码，但可能只是遗漏了一些我认为可以帮助我的东西。 这里是index.php ，显示我的数据库中的表

<?php
//include auth.php file on all secure pages
require("../db.php");
session_start();
if(!isset($_SESSION["username"])){
header("Location: login");
exit(); }
?>
<?php require_once('header.php')?>  

<div class="container content">


  <table id="myTable" class="table table-striped" >  
        <thead>  
          <tr>
       <th>ConsignmentNo</th>
        <th>Origin</th>
        <th>Destination</th>
        <th>PickupDate</th>
        <th>Status</th>
        <th >Actions</th>
        </tr>
        </thead>
            <tbody>
                <?php
                $result = mysqli_query($con,"SELECT * FROM consignment");
                 while($row = mysqli_fetch_array($result)) {
                    echo "<tr>";
                echo "<td>" . $row['consignmentno'] . "</td>";
                echo "<td>" . $row['shipmentorigin'] . "</td>";
                echo "<td>" . $row['shipmentdestination'] . "</td>";
                echo "<td>" . $row['shipmentpickupdate'] . "</td>";
                echo "<td>" . $row['shipmentstatus'] . "</td>";
                echo "<td><a name='consignmentno' href='update.php?id=".$row['consignmentno']."'>Edit</a></td>";
                echo "</tr>";
                                                    }
                mysqli_close($con);
                ?>
            </tbody>
      </table>  
      </div>






</div>

<?php require_once('footer.php')?>

这是处理我的请求的 update.php 页面

<?php
require("../db.php");
$track = $_GET['consignmentno']; 
$sql = "SELECT * FROM `consignment` WHERE consignmentno='$track'";
$result = $con->query($sql);

if ($result->num_rows > 0) {

     // output data of each row
     while($row = $result->fetch_assoc()) {

$consignmentno = $row['consignmentno'];

$shippername = $row['shippername'];

$shipperphone = $row['shipperphone'];

$shipperaddress = $row['shipperaddress'];

$shipperemail = $row['shipperemail'];

$receivername = $row['receivername'];

$receiverphone = $row['receiverphone'];

$receiveraddress = $row['receiveraddress'];

$receiveremail = $row['receiveremail'];

$shipmenttype = $row['shipmenttype'];

$shipmentweight = $row['shipmentweight'];

$shipmentcourier = $row['shipmentcourier'];

$shipmentpackage = $row['shipmentpackage'];

$shipmentmode = $row['shipmentmode'];

$shipmentproduct = $row['shipmentproduct'];

$shipmentquantity = $row['shipmentquantity'];

$shipmentfrieght = $row['shipmentfrieght'];

$shipmentcarrier = $row['shipmentcarrier'];

$departeddate = $row['departeddate'];

$shipmentorigin = $row['shipmentorigin'];

$shipmentdestination = $row['shipmentdestination'];

$shipmentpickupdate = $row['shipmentpickupdate'];

$shipmentstatus = $row['shipmentstatus'];

$shipmentexpected = $row['shipmentexpected'];

$comment = $row['comment'];
     }

} else {
     echo "NO DETAILS FOR USER";
}

$con->close();
?>
<?php require_once('header.php')?>  

<div class="container content">
<script type="text/javascript">

$(document).ready(function(){


txt=$("#UpdateStatus").val();



if(txt=='3')
{

$("#receive").slideDown("slow");

$("#UpdateReceivedBy").removeAttr("disabled");
}
else
{
$("#receive").slideUp("slow");
 $('#UpdateReceivedBy').attr('disabled', 'true');

}


  $("#UpdateStatus").change(function(){

       txt=$("#UpdateStatus").val();



if(txt=='3')
{
$("#receive").slideDown("slow");
$("#UpdateReceivedBy").removeAttr("disabled");
}
else
{
$("#receive").slideUp("slow");
 $('#UpdateReceivedBy').attr('disabled', 'true');

}



  });
});

</script>


<h2 class="col-md-offset-5">Update Shipment</h2>





     <div class="row">
     <div class="table-responsive col-md-8 col-md-offset-2">

     <table class="table table-bordered table-hover">

     <thead>
          <tr>
            <th><h4><?php echo $consignmentno ; ?></h4> 

            </th>

            <th>

<h2>On Hold</h2>     
      </th>

          </tr>
        </thead>

但它没有回应$consignmentno因为它可以做到这一点然后其他所有事情变得更容易

这是一张图片，显示我的索引页面工作正常

所以请帮我检查一下我弄错了。感谢

Answer 1

您必须将update.php?id=替换为update.php?consignmentno=，line 35它将解决您的问题

或者在 index.php

中使用此代码

<?php
//include auth.php file on all secure pages
require("../db.php");
session_start();
if(!isset($_SESSION["username"])){
header("Location: login");
exit(); }
?>
<?php require_once('header.php')?>  

<div class="container content">


  <table id="myTable" class="table table-striped" >  
        <thead>  
          <tr>
       <th>ConsignmentNo</th>
        <th>Origin</th>
        <th>Destination</th>
        <th>PickupDate</th>
        <th>Status</th>
        <th >Actions</th>
        </tr>
        </thead>
            <tbody>
                <?php
                $result = mysqli_query($con,"SELECT * FROM consignment");
                 while($row = mysqli_fetch_array($result)) {
                    echo "<tr>";
                echo "<td>" . $row['consignmentno'] . "</td>";
                echo "<td>" . $row['shipmentorigin'] . "</td>";
                echo "<td>" . $row['shipmentdestination'] . "</td>";
                echo "<td>" . $row['shipmentpickupdate'] . "</td>";
                echo "<td>" . $row['shipmentstatus'] . "</td>";
                echo "<td><a name='consignmentno' href='update.php?consignmentno=".$row['consignmentno']."'>Edit</a></td>";
                echo "</tr>";
                                                    }
                mysqli_close($con);
                ?>
            </tbody>
      </table>  
      </div>
</div>

<?php require_once('footer.php')?>

使用php和mysqli从表中选择和更新表单

1 个答案: