Question

我正在尝试编写二进制翻译器 - 将字符串作为输入，将二进制表示作为输出。

我遇到了一些困难，我在变量中写了每个字母的翻译，但它们是变量，而不是字符串，所以我想从变量的名称中获取输入的输入并输出结果：

a = "01000001"
b = "01000010"
c = "01000011"
d = "01000100"
# all the way to z


word = input("enter here: ")
print (word)

当我运行这个时，我输入一个单词，它只是向我返回相同的单词，但是当我写print(a)时，它返回01000010但我无法使用输入。< / p>

有人可以告诉我我做错了什么吗？

Answer 1

根据用户的评论，对于这些案例使用字典编程是一种更好的做法，您只需要填写字典letterToBin，如示例中所示

这是一本字典，意思是它有一把钥匙和一个价值，比如一部手机，你有钥匙作为名字（你的母亲）和价值（他的手机）：

letterToBin = {}

letterToBin = {
  "a" : "01000001", #Here, the key is the "a" letter, and the value, his bin transformation, the 01000001
  "b" : "01000010",
  "c" : "01000011",
  "d" : "01000100"
  #so you need to add all the other keys you need, for example the "e"
  "e" : "01000101" #for example
}




binToLetter = {} # here I create a second dictionary, and it invert the values of the first, it meas, now the keys will be the bins, and the value the latters
binToLetter = dict(zip(letterToBin.values(), letterToBin.keys())) #this code do the magic, you must understand, that only needs to feel the first dictionary, and for free, you will have the second dictionary

wordOrBin = input("enter here: ")

if wordOrBin in letterToBin:
  print(letterToBin[wordOrBin]) #here I has if you write a latter (a) or a bin(11001101) and it choose where to look the correct value
else:
  print(binToLetter[wordOrBin])

Answer 2

可能更正确的解决方案是使用字典而不是字母名称作为变量名称：

transDict = {
    "a": "01100001",
    "b": "01100010",
    "c": "01100011",
    "d": "01100100",
    # etc., etc.
    }

text   = input( "Enter your message: " )

result = "".join( [transDict[letter] for letter in text] )

print(result)

（我还更正了ASCII代码 - 您的代码是大写字母。）

解释
（最长的陈述）：

“使用""作为分隔符（即no delimiter）加入 已翻译字母列表中的所有项目其他来自text“。

所以结果与使用这些命令的结果相同：

listOfCodes = []                     # Starting with an empty list
for letter in text:                  # For letter by letter in text perform 2 actions:
    code = transDict[letter]         #   - translate the letter
    listOfCodes.append( code )       #   - append the translation to the list

result = "".join( listOfCodes )      # Then join items of the list without a delimiter 
                                     # (as "" is an empty string) (" " would be nicer)

Python中的二进制文本

2 个答案: