Question

我必须在laravel中构建登录。通常没问题。但我的客户想要使用一些特殊用户名登录。它应该是surname-userId。

所以有用户表：

id; firstname; lastname; email; ...
1; testuser1; Smith; testuser1.smith@anyprovider.xx;

此处的登录名应为“Smith-1”。我刚刚找到了覆盖LoginController中的函数username（）的解决方案。但在这种情况下，我需要组合两个表字段来构建用户名。

以前是否有人这样做过？

Answer 1

只是重载方法attemptLogin

Answer 2

就像哈萨诺夫所说的那样，重载attemptLogin函数就足够了。 EloquentUserProvider使用给定的凭据构建查询：

   /**
     * Retrieve a user by the given credentials.
     *
     * @param  array  $credentials
     * @return \Illuminate\Contracts\Auth\Authenticatable|null
     */
    public function retrieveByCredentials(array $credentials)
    {
        if (empty($credentials)) {
            return;
        }

        // First we will add each credential element to the query as a where clause.
        // Then we can execute the query and, if we found a user, return it in a
        // Eloquent User "model" that will be utilized by the Guard instances.
        $query = $this->createModel()->newQuery();

        foreach ($credentials as $key => $value) {
            if (! Str::contains($key, 'password')) {
                $query->where($key, $value);
            }
        }

        return $query->first();
    }

所以我只是将输入的用户名分成两个字段，UserProvider完成剩下的工作：

/**
 * Attempt to log the user into the application.
 *
 * @param  \Illuminate\Http\Request  $request
 * @return bool
 */
protected function attemptLogin(Request $request)
{
    $credentials = $this->credentials($request);

    list($lastname, $id) = explode('-', $credentials[$this->username()]);

    $params = [
        'id' => (int) $id,
        'name' => $lastname,
        'password' => $credentials['password'],
    ];

    return $this->guard()->attempt(
        $params, $request->has('remember')
    );
}

laravel身份验证：使用组合用户名

2 个答案: