Question

我正在调用一个restful服务来获取服务器上的可用文档，我将JSON作为响应。我正在使用JSONBuilder构建JSON字符串，因此在调用此链接时

http://localhost:8080/httpConnector/Rest/Documents?Accept=application/json

我正在获取下面的JSON字符串：

String accept = getValue("Accept");
accept = "application/xml";                
if ("application/xml".equals(accept)){
    builder=new groovy.xml.MarkupBuilder(writer);
}else{
    builder=new groovy.json.JsonBuilder();
}

   builder{
    results foaList.collect{
        [
                  //Here I want to loop through the otaList to do something like that "ota.getName(), foa.getFlexiObject().getByString(ota.getName())"
          result:   [
                  name: it.getFlexiObject().getByString("name"),
              version: it.getFlexiObject().getByString("version"),
               author: it.getFlexiObject().getByString("author")
                ] 
        ]
    }

}

代码

builder.'results'() {
    for(FlexiObjectAttachment foa: foaList){
        for(ObjectTypeAttribute ota : otaList){
            param.put(ota.getName(), foa.getFlexiObject().getByString(ota.getName()));

        }
        result(param);
    }       
}

现在我想以编程方式添加属性。因此，我必须遍历otaList来做类似的事情

 for (key, value) in photoDic {
        if  let url = URL.init(string: value as! String){
        let photo : PhotoRecord = PhotoRecord.init(name:key as! String, url:url)
        self.photoRecords.append(photo)
        }
    }

此版本仅适用于xml respose。

Answer 1

您可以尝试直接在foa电话中结合使用ota和collect。这样你最初创建的dict就会有正确的结构。

类似下面的示例

def foaList = [1, 2, 3, 4]
def otaList = ['A', 'B', 'C']

foaList.collect { foa ->
    result = [name: "Name$foa", version: "v$foa", author: "Author$foa"]
    otaList.each { ota -> result[ota] = "$ota$foa" }
    [ result: result ]
}

在构建JSON字符串时迭代两个循环

1 个答案: