Question

我有这个字符串：

$string = ["coffee candy (123456789) (Amount: 0.00 EUR)",
           "fruity candy (987654332) (Amount: 0.00 EUR)"];

我希望结果如下：

array(2) {
 [0] => array {
    ["name"] => string(12) coffee candy
    ["num"] => string(9) 123456789
    ["amount"] => string(15) Amount 0.00 EUR
 }
 [1] => array {
    ["name"] => string(12) fruity candy
    ["num"] => string(9) 987654332
    ["amount"] => string(15) Amount 0.00 EUR        
 }
}

或类似的东西。是否可以使用正则表达式？如果是这样，怎么样？

Answer 1

您可以使用字符(展开字符串，然后修剪)，查看live demo

<?php

$string = ["coffee candy (123456789) (Amount: 0.00 EUR)",
           "fruity candy (987654332) (Amount: 0.00 EUR)"];
$keys = ['name', 'num', 'amount'];          
$array = array_map(function($v) use($keys) {
  $arr = explode('(', $v);
  $arr = array_map(function($v){
    return trim($v, " \t\n\r\0\x0B)");
  }, $arr);
  return array_combine($keys, $arr);
}, $string);

print_r($array);

Answer 2

如果输入是一致的（机器生成的）我会删除正则表达式并执行类似的操作

$array = explode(',',$string);
foreach($array as $data){
    $parts = explode('(',$data);
    $result[]['name'] = trim(substr($parts[0], 1));
    $result[]['num'] = trim(substr($parts[1], 0, -1));
    $result[]['amount'] = trim(substr($parts[2], 0, -2));
}

但是这只适用于一致的字符串。

Answer 3

我认为你需要这样的东西

<?php
$text = 'coffee candy (123456789) (Amount: 0.00 EUR)';

preg_match('/^([a-zA-Z\s]+)\s+?\(([\d]+)\)\s+?\((.+)\)/', $text, $matches);
print_r($matches);

使用regex将字符串转换为数组

3 个答案: