Question

我开始编写我的第一个线程教程，我正在创建一个单线程生产者和消费者。尚未完成，同步仍在继续。但它没有编译，我不明白这个错误意味着哪个论点缺失或错误。以下是我的代码。

#include<iostream>
#include<thread>
#include<sstream>
#include<list>
#include<mutex>
#include<Windows.h>

using namespace std;

#define BUCKET_LEN 5

HANDLE gMutex = NULL;
HANDLE gSemFull = NULL;
HANDLE gSemEmpty = NULL;

class producerConsumer  {
    long i;
    list<wstring> que;
public:
    producerConsumer() {
        i = 0;
        que.clear();
    }
    void produce();
    void consumer();
    void startProducerConsumer();
};

void producerConsumer::produce() {
    std::wstringstream str;
    str << "Producer["  <<"]\n";
    que.push_back(str.str());
}

void producerConsumer::consumer() {
    wstring s = que.front();
    cout << "Consumer[" << "]";
    wcout << " " << s;
    que.pop_front();
}

void producerConsumer::startProducerConsumer() {
    std::thread t1(&producerConsumer::produce);
    std::thread t2(&producerConsumer::consumer);
    t1.joinable() ? t1.join() : 1;
    t2.joinable() ? t2.join() : 1; 
}

int main()
{
    gMutex = CreateMutex(NULL, FALSE, NULL);
    if (NULL == gMutex) {
        cout << "Failed to create mutex\n";
    }
    else {
        cout << "Created Mutex\n";
    }

    producerConsumer p;
    p.startProducerConsumer();

    if (ReleaseMutex(gMutex)) {
        cout << "Failed to release mutex\n";
    }
    else {
        cout << "Relested Mutex\n";
    }
    gMutex = NULL;
    system("pause");
    return 0;
}

Answer 1

非静态成员函数需要调用对象。该对象可以作为指针或引用作为std::thread构造函数的第二个参数传递：

std::thread t1(&producerConsumer::produce, this);
std::thread t2(&producerConsumer::consumer, this);

在线程错误C2064中：术语不评估为采用0参数的函数

1 个答案: