Hibernate Inner Join OneToMany Mapping抛出HibernateQueryException

时间:2017-05-28 23:13:00

标签: java mysql hibernate

我是Hibernate的新手。我在OneToManyUser之间建立了Expense映射。我正在尝试为User返回last week的费用。 这是我正在使用的MySQL查询。

select SUM(amount) from Expense INNER JOIN User ON Expense.user_id = User.id AND User.username ='testUser' WHERE created >= curdate() - INTERVAL DAYOFWEEK(curdate())+1 DAY AND created < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY;

当我尝试在hibernate中使用此查询时,我得到HibernateQueryException

 String query = "select SUM(amount) from Expense INNER JOIN User ON Expense.user_id = User.id AND user.username ='sarvam' WHERE created >= curdate() - INTERVAL DAYOFWEEK(curdate())+1 DAY AND created < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY";
 List list = session.createQuery(query).list();

我得到的错误是 -

Exception in thread "main" org.hibernate.QueryException: outer or full join must be followed by path expression [select SUM(amount) from com.challenge.pojo.Expense INNER JOIN User ON Expense.user_id = User.id AND user.username ='sarvam' WHERE created >= curdate() - INTERVAL DAYOFWEEK(curdate())+1 DAY AND created < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY]
    at org.hibernate.QueryException.generateQueryException(QueryException.java:120)
    at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103)
    at org.hibernate.hql.internal.classic.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:233)
    at org.hibernate.hql.internal.classic.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:193)
    at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:115)
    at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:76)
    at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:150)
    at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:298)
    at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236)
    at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1825)
    at com.challenge.dao.ExpenseDAO.getExpensesForLastWeek(ExpenseDAO.java:52)
    at com.challenge.dao.ExpenseDAO.getExpensesForLastWeek(ExpenseDAO.java:44)
    at com.challenge.dao.Test.main(Test.java:27)
Caused by: org.hibernate.QueryException: outer or full join must be followed by path expression
    at org.hibernate.hql.internal.classic.FromParser.token(FromParser.java:253)
    at org.hibernate.hql.internal.classic.ClauseParser.token(ClauseParser.java:93)
    at org.hibernate.hql.internal.classic.PreprocessingParser.token(PreprocessingParser.java:118)
    at org.hibernate.hql.internal.classic.ParserHelper.parse(ParserHelper.java:43)
    at org.hibernate.hql.internal.classic.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:223)
    ... 10 more

任何人都可以帮我修复它。

2 个答案:

答案 0 :(得分:1)

  

createQuery(String queryString)为。创建一个新的Query实例   给出HQL查询字符串。

     

createSQLQuery(String queryString)             为给定的SQL查询字符串创建一个新的SQLQuery实例。

您正在使用第一个期望HQL作为输入的人,对于使用本机SQL,您可以使用第二个。

update t
    set col = replace(col, '  ', ', ')
    where col like '%  %';

Session Documentation

答案 1 :(得分:0)

您可能需要查看:I can't make a inner join between two tables in hibernate hql query

如果使用HQL,您必须使用面向对象的样式,它们可能如下所示:

String query = "select SUM(amount) from Expense exp INNER JOIN User u ON e.user_id = u.id AND u.username = 'sarvam' ...";
List list = session.createQuery(query).list();

(未测试的)

或者,如果您改为使用:

,则可以继续使用标准SQL合成代码
List list = session.createSQLQuery(query).list();

然后您可能想要阅读Hibernate文档的Chapter 16

请记住,SQL方言取决于底层数据库。根据您的应用程序,可能在不同的系统上使用不同的数据库,这可能会破坏您的SQL语句。