这是使用查询创建的视图:SELECT title,count(*)as views FROM articles a,log l WHERE a.slug = substring(l.path,10)GROUP BY title ORDER BY views DESC;
title | views
------------------------------------+--------
article-1 | 338647
article-2 | 253801
article-5 | 170098
article-3 | 84906
article-8 | 84810
article-7 | 84557
article-6 | 84504
article-4 | 84383
现在我正在尝试使用此视图创建一个查询,以打印出与标题关联的每个作者的文章视图总和。下面我重新创建了其他两个表的关键列。
AUTHORS
name | id
---------------------+--------
author-1 | 1
author-2 | 2
author-3 | 3
author-4 | 4
ARTICLES
author | article
--------------+--------
1 | article-1
2 | article-2
1 | article-3
4 | article-4
1 | article-5
1 | article-6
3 | article-7
2 | article-8
答案 0 :(得分:0)
你会这样做:
select a.author, sum(v.views) as view
from yourview v join
articles a
on v.title = a.article join
authors au
on a.author = au.id
group by a.author;