Question

我有这个程序（Python）：

import re

line = "This is a phone number: (061) - 535555. And this is another: 01 - 4657289, 9846012345"

foundNum = re.search(r'((\(?\d{2,3}\)?\D{0,3}\d{6,10})|\d{10})', line)

print("The phone numbers found are: ", foundNum.groups())

我试图从'line'字符串中提取所有电话号码（可能是另一个文本块），但它没有给出预期的结果，只有一个值（第一个电话号码）重复两次。我错过了什么？

Answer 1

您应该使用finditer。

import re

line = "This is a phone number: (061) - 535555. And this is another: 01 - 4657289, 9846012345"

foundNum = re.finditer(r'((\(?\d{2,3}\)?\D{0,3}\d{6,10})|\d{10})', line)
for i in foundNum:
    print(i.group())

或findall：

import re

line = "This is a phone number: (061) - 535555. And this is another: 01 - 4657289, 9846012345"

foundNum = re.findall(r'((\(?\d{2,3}\)?\D{0,3}\d{6,10})|\d{10})', line)
print("The phone numbers found are: ", *foundNum)

Answer 2

您可以使用findall代替search，也可以取消嵌套捕获组：

foundNum = re.findall(r'(\(?\d{2,3}\)?\D{0,3}\d{6,10}|\d{10})', line)
print("The phone numbers found are: ", foundNum)

<强>结果：

('The phone numbers found are: ', ['(061) - 535555', '01 - 4657289', '9846012345'])

re.search()在字符串中搜索 第一次 出现的RE模式，这就是为什么它只返回第一个匹配。表达式re.findall()将字符串中模式的所有非重叠匹配作为字符串列表返回。

Answer 3

您可以使用（demo on regex101.com）：

\(?\d[- \d()]*\d

细分说：

\(?       # match ( eventually
\d        # match a digit
[- \d()]* # one of "-", "0-9", "(", ")" or " ", zero or more times
\d        # another digit

这确保了开头和结尾至少有一个数字。

RegEx废话电话号码

3 个答案: