Question

我是SQL的新手，所以寻求一些帮助。继承我的代码

Select
    MITARBEITER_NR "ID",
   DAUER "Duration",
datum "Date"
From
Vtsbreak 
Where DATUM >= TO_DATE('2017/04/01', 'yyyy/mm/dd') AND DATUM <= TO_DATE('2017/05/27','yyyy/mm/dd') 
order by datum

这是我的数据

ID  Duration    Date
443 60  03/04/2017
412 10  03/04/2017
399 100 04/04/2017
374 10  04/04/2017
374 10  04/04/2017
376 120 04/04/2017
456 300 04/04/2017
372 120 04/04/2017
443 60  04/04/2017
446 300 04/04/2017
427 60  04/04/2017
403 420 04/04/2017

我要做的是返回ID代码，日期，该日期的持续时间总和我尝试过使用group但是只返回一个id为374的案例，时间为04/04/2017，值为10而不是20

有什么建议吗？

Answer 1

你想要一个GROUP BY。按照您使用的语法（但绝对不是MySQL），您可以执行以下操作：

select MITARBEITER_NR as id,
       to_char(datum, 'YYYY-MM-DD') as yyyymmdd,
       sum(dauer) as duration
from Vtsbreak 
where datum >= DATE '2017-04-01' and
      datum < DATE '2017-05-28'
group by id, to_char(datum, 'YYYY-MM-DD')
order by yyyymmdd;

Answer 2

排序

Select
    MITARBEITER_NR "ID",
   sum(DAUER) "Duration",
   datum "Date"
From
Vtsbreak 
Where DATUM >= TO_DATE('2017/04/01', 'yyyy/mm/dd') AND DATUM <= TO_DATE('2017/05/27','yyyy/mm/dd') 
group by MITARBEITER_NR, datum;
order by datum

SQL语句组？还是总结？

2 个答案: