如何使用Pig在列表中为相同的密钥存储不同的值

Question

我有一个用例

col1|col2
a101|10
a101|20
a101|10
a101|30
a201|40
a201|50

预期产出：

A101 |列表与LT; 10,20,30＆GT;

A201 |列表与LT; 40,50＆GT;

以下是查询，但我没有按预期获得输出。我想将col2不同的值存储在列表中。

input1= load 'list1.csv' using PigStorage('|') as (col1: chararray, col2: int);
input2 = DISTINCT (FOREACH input1 generate col1,col2);
input3 = GROUP input2 by col1;
dump input3;
(a101,{(a101,30),(a101,20),(a101,10)})
(a201,{(a201,50),(a201,40)})

Answer 1

试试这个：

input1= load 'input.txt' using PigStorage('|') as (col1: chararray, col2: int);
input2 = DISTINCT input1; --distinct not required but will remove duplicate rows 
input3 = GROUP input2 by col1;
data = FOREACH input3 GENERATE FLATTEN(group) as col1, input2.col2 AS col2;
DUMP data;

输出生成：

(a101,{(30),(20),(10)})
(a201,{(50),(40)})