Question

我在php中开发了一个Windows Web服务器，我想使用php-cgi。它运行良好，但我遇到了GET和POST请求问题。当我设置环境变量＆＃34; REQUEST_METHOD＆＃34;到＆＃34; POST＆＃34;，我在$ _POST变量中没有得到任何东西，但是我在$ _GET中得到了内容：/它没有任何意义......

这是我的代码：

Process php = new Process();
php.StartInfo.FileName = "C:/PHP-7.1/php-cgi.exe";
php.StartInfo.RedirectStandardOutput = true;
php.StartInfo.UseShellExecute = false;
php.StartInfo.EnvironmentVariables["GATEWAY_INTERFACE"] = "CGI/1.1";
php.StartInfo.EnvironmentVariables["SCRIPT_FILENAME"] = page;
php.StartInfo.EnvironmentVariables["REQUEST_METHOD"] = "POST";
php.StartInfo.EnvironmentVariables["REDIRECT_STATUS"] = "true";
php.StartInfo.EnvironmentVariables["SERVER_PROTOCOL"] = "HTTP/1.1";
php.StartInfo.EnvironmentVariables["SERVER_SOFTWARE"] = ServerVersion;
php.StartInfo.EnvironmentVariables["REMOTE_HOST"] = "127.0.0.1";
//php.StartInfo.EnvironmentVariables["CONTENT_LENGTH"] = "3"; // Causes crash
php.StartInfo.EnvironmentVariables["HTTP_ACCEPT"] = "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8";
php.StartInfo.EnvironmentVariables["CONTENT_TYPE"] = "text/html";
String QueryString = "";
if (request.GET_Variables.Count() > 0)
{
    int i = 0;
    foreach (String variable in request.GET_Variables)
    {
        QueryString += variable + "=" + request.GET_Values[i];
        i++;
        if (i != request.GET_Variables.Count())
        {
            QueryString += "&";
        }
    }
}
php.StartInfo.EnvironmentVariables["QUERY_STRING"] = QueryString;
php.StartInfo.Arguments = "-f \"" + page + "\"";
Console.WriteLine("php-cgi.exe " + php.StartInfo.Arguments); // Debug
php.Start();

例如，如果：

QUERY_STRING="fox=brown&dog=lazy"

var_dump（）;会是这样的：

GET: array(2) { ["fox"]=> string(5) "brown" ["dog"]=> string(4) "lazy" }
POST: array(0) { }

我希望有人可以帮助我，祝你有愉快的一天！

php-cgi POST请求无缘无故变成GET请求

0 个答案: