Python pyodbc：解析JSON列表是错误的

Question

我正在解析来自Yelp的JSON响应：

{
  "businesses": [
    {
      "id": "gaumont-wilson-toulouse-2",
      "name": "Gaumont Wilson",
      "city": "Toulouse"           
       }
    {
      "id": "la-cinémathèque-de-toulouse-toulouse",
      "name": "La Cinémathèque de Toulouse",
      "city": "Toulouse"
       }
    {
      "id": "abc-toulouse",
      "name": "ABC",
      "city": "Toulouse"
       }
  ]
}

我写了我的Python代码：

for element in response_data['businesses']:
    SQL_ID = element['id']
    SQL_Name = element['name']
    SQL_City = element['city']
    cursor.execute("INSERT INTO Yelp (ID, Name, City) values (?,?,?)", (SQL_ID,SQL_Name,SQL_City))
    connection.commit()

但结果是Python只是通过了最后的业务，而不是前两个：

为什么？

Answer 1

您是否使用json.loads()加载了json？如果你没有，请尝试以下方法。

import json

reponse_data_json = json.loads(response_data)
for element in response_data_json['businesses']:
    SQL_ID = element['id']
    SQL_Name = element['name']
    SQL_City = element['city']
    cursor.execute("INSERT INTO Yelp (ID, Name, City) values (?,?,?)", (SQL_ID,SQL_Name,SQL_City))
    connection.commit()

Answer 2

您的数据不是有效的json格式，我做了一些改动以添加＆＃39;，＆＃39;在每个{}之后，然后您可以检索以下所有内容，在python 3.6下测试代码

 data =  {
  "businesses": [
     {
       "id": "gaumont-wilson-toulouse-2",
       "name": "Gaumont Wilson",
       "city": "Toulouse"           
     },

     {
       "id": "la-cinémathèque-de-toulouse-toulouse",
       "name": "La Cinémathèque de Toulouse",
       "city": "Toulouse"
      },
    {
       "id": "abc-toulouse",
       "name": "ABC",
       "city": "Toulouse"
       },
  ]
}

 jsonobject = json.dumps(data)

 jsonobjectToString = json.loads(jsonobject)
 for resp in jsonobjectToString['businesses']:
     print(resp['id'])
     print(resp['name'])
     print(resp['city'])

=======

  gaumont-wilson-toulouse-2
  Gaumont Wilson
  Toulouse
  la-cinémathèque-de-toulouse-toulouse
  La Cinémathèque de Toulouse
  Toulouse
  abc-toulouse
  ABC
  Toulouse