我现在想到的是创建AllTest
并使用junit运行它。但是,我对此并不满意。我希望这个规则可以创建与在codebase中创建的许多java测试文件一样多的测试。
def junit_suite_test(name, srcs, deps, size="small", resources=[], classpath_resources=[], jvm_flags=[], tags=[], data=[]):
tests = []
package = PACKAGE_NAME.replace("src/test/java/", "").replace("/", ".")
for src in srcs:
if src.endswith("Test.java"):
if "/" in src:
src = package + "." + src.replace("/", ".")
tests += [src.replace(".java", ".class")]
native.genrule(
name = name + "-AllTests-gen",
outs = ["AllTests.java"],
cmd = """
cat <<EOF >> $@
package %s;
import org.junit.runner.RunWith;
import org.junit.runners.Suite;
@RunWith(Suite.class)
@Suite.SuiteClasses({%s})
public class AllTests {}
EOF
""" % (package, ",".join(tests))
)
native.java_test(
name = name,
srcs = srcs + ["AllTests.java"],
test_class = package + ".AllTests",
resources = resources,
classpath_resources = classpath_resources,
data = data,
size = size,
tags = tags,
jvm_flags = jvm_flags,
deps = deps + [
],
)
答案 0 :(得分:2)
嗨,你可以这样做:
[java_test(name = s[:-5], srcs = s) for s in glob(["*.java"])]
这将在每个java文件的测试目标上创建。
使用该方法,您的宏看起来像:
def junit_suite_test(name, srcs, deps, size="small", resources=[], classpath_resources=[], jvm_flags=[], tags=[], data=[]):
[native.java_test(
name = name,
srcs = src,
resources = resources,
classpath_resources = classpath_resources,
data = data,
size = size,
tags = tags,
jvm_flags = jvm_flags,
deps = deps,
) for src in srcs if src.endswith("Test.java")]
当然,您可能需要进行一些调整以获得良好的资源。
但是,我建议不要对你的解决方案这样做,因为过多的并行性实际上可能会更慢。测试日志和XML文件将报告实际失败的测试用例,您可以使用shard_count来增加并行性。