MainWindow.xaml
<Window.Resources>
<DataTemplate DataType="{x:Type local2:StartPageViewModel}">
<local1:StartPage/>
</DataTemplate>
<DataTemplate DataType="{x:Type local2:SecondPageViewModel}">
<local1:SecondPage/>
</DataTemplate>
</Window.Resources>
<DockPanel>
<StackPanel DockPanel.Dock="Left">
<Label Content="[res][per]" />
<Button Command="{Binding CommandStartView}">
First
</Button>
<Button Command="{Binding CommandSecondView}">
Second
</Button>
</StackPanel>
<ContentControl x:Name="Pages" DockPanel.Dock="Right" Content="{Binding SelectedViewModel}"/>
</DockPanel>
MainWindowViewModel.cs
class MainWindowViewModel : BaseViewModel
{
private object selectedViewModel;
public object SelectedViewModel
{
get { return selectedViewModel; }
set { selectedViewModel = value; OnPropertyChanged("SelectedViewModel"); }
}
public ICommand CommandStartView { get; set; }
public ICommand CommandSecondView { get; set; }
public MainWindowViewModel()
{
CommandStartView = new RelayCommand(openStartView);
CommandSecondView = new RelayCommand(openSecondView);
}
private void openStartView(object obj)
{
SelectedViewModel = new StartPageViewModel();
}
private void openSecondView(object obj)
{
SelectedViewModel = new SecondPageViewModel();
}
}
StartPage.xaml
<StackPanel>
<Label Content="First Page" />
<Button Content="Second" Command="{Binding Path=DataContext.CommandSecondView, RelativeSource={RelativeSource AncestorType={x:Type Window}}}"/>
<Button Content="Do Something" Command="{Binding CommandDoBeforeSecondView}"/>
</StackPanel>
StartPageViewModel.cs
class StartPageViewModel : BaseViewModel
{
public ICommand CommandDoBeforeSecondView { get; set; }
public StartPageViewModel()
{
CommandDoBeforeSecondView = new RelayCommand(openSecondView);
}
private void openSecondView(object obj)
{
Console.WriteLine("DO SOME CODE");
//Then change Content programmatically
}
}
问题: 如何使用StartPage中的第二个按钮从MainWindow ContentControl更改内容?我想执行一些代码,然后更改内容。
关于第一条评论我认为我必须在我的StartPageViewModel中添加一个MainWindowViewModel的引用,我是如何做到的?
修改
我的工作解决方案:
MainWindowViewModel.cs
private void openStartView(object obj)
{
SelectedViewModel = new StartPageViewModel(this);
}
StartPageViewModel.cs
class StartPageViewModel : BaseViewModel
{
private MainWindowViewModel mainWindow;
public ICommand CommandDoBeforeSecondView { get; set; }
public StartPageViewModel(MainWindowViewModel _mainWindow)
{
mainWindow = _mainWindow;
CommandDoBeforeSecondView = new RelayCommand(openSecondView);
}
private void openSecondView(object obj)
{
Console.WriteLine("DO SOME CODE");
mainWindow.SelectedViewModel = new SecondPageViewModel();
}
}
答案 0 :(得分:0)
我的工作解决方案:
MainWindowViewModel.cs
private void openStartView(object obj)
{
SelectedViewModel = new StartPageViewModel(this);
}
StartPageViewModel.cs
class StartPageViewModel : BaseViewModel
{
private MainWindowViewModel mainWindow;
public ICommand CommandDoBeforeSecondView { get; set; }
public StartPageViewModel(MainWindowViewModel _mainWindow)
{
mainWindow = _mainWindow;
CommandDoBeforeSecondView = new RelayCommand(openSecondView);
}
private void openSecondView(object obj)
{
Console.WriteLine("DO SOME CODE");
mainWindow.SelectedViewModel = new SecondPageViewModel();
}
}
向Peter Duniho致谢,他回答了上述评论:
你应该在MainWindowViewModel中创建StartPageViewModel时传递它,然后StartPageViewModel将有引用(你当然必须将参数添加到构造函数中)