这是app.js文件:
var express = require('express');
var routes = require('./routes/index');
app = express();
app.use('/', routes);
// catch 404 and forward to error handler
app.use(function(req, res, next) {
var err = new Error('Not Found');
err.status = 404;
next(err); //res.render('404')
});
和routes / index.js:
var express = require('express')
, router = express.Router()
var importer = require('./../lib/importer')
, importRoutes = importer(__dirname)
, routes = {
views: importRoutes('./views')
};
router.get('/login', routes.views.login.get);
router.post('/login', routes.views.login.post);
router.get('/register', routes.views.register.get);
... and many other routes (more than 50)
router.get('/theLastRoute', routes.views.auth.oneOfTheLastRoutes.get);
module.exports = router;
但是如果我从应用程序响应404的底部转到localhost:3000/oneOfTheLastRoutes
或某条路线,即使这条路线确实存在于routes / index.js中,如果我在模块中将此路线移到更高位置,该应用程序将给出正确的回应。
我几乎可以确定问题出在lib / importer.js中,其中一些异步代码需要来自routes / views文件夹的所有路由,而不是所有路由都分配给rotutes.view属性。
importer.js:
var fs = require('fs');
var path = require('path');
function dispatchImporter (rel__dirname) {
function importer (from) {
//console.log('importing ', from);
var imported = {};
var joinPath = function () {
return '.' + path.sep + path.join.apply(path, arguments);
};
var fsPath = joinPath(path.relative(process.cwd(), rel__dirname), from);
fs.readdirSync(fsPath).forEach(function (name) {
var info = fs.statSync(path.join(fsPath, name));
//console.log(name);
if (info.isDirectory()) {
imported[name] = importer(joinPath(from, name));
} else {
// only import files that we can `require`
var ext = path.extname(name);
var base = path.basename(name, ext);
if (require.extensions[ext]) {
imported[base] = require(path.join(rel__dirname, from, name));
} else {
console.log('cannot require ', ext);
}
}
});
return imported;
}
return importer;
}
module.exports = dispatchImporter;
我没有设法提出一个解决方案,在404处理程序之前需要所有路径文件并将其分配给routes
对象。
文件结构如下:
app.js
lib/
importer.js
routes/
index.js
views/
login.js
register.js
etc...
答案 0 :(得分:0)
问题结果发生在其他模块中,其中声明了重叠路线。