Question

在尝试将此网站放在一起时，我在编写允许版主添加产品的功能时遇到了问题。我附上了我得到的代码和错误信息。

功能（来自product-model.php）：

function insPro(){

// Create a connection object using the acme connection function
   $db = acmeConnect();
// The SQL statement
   $sql = 'INSERT INTO inventory (invName, invDescription, invImage, invThumbnail, invPrice, invStock, invSize, invWeight, invLocation, categoryId, invVendor, invStyle)
       VALUES (:invName, :invDescription, :invImage, :invThumbnail, :invPrice, :invStock, :invSize, :invWeight, :invLocation, :categoryId, :invVendor, :invStyle)';
// Create the prepared statement using the acme connection
   $stmt = $db->prepare($sql);
   $stmt->bindValue(':invName', $invName, PDO::PARAM_STR);
   $stmt->bindValue(':invDescription', $invDescription, PDO::PARAM_STR);
   $stmt->bindValue(':invImage', $invImage, PDO::PARAM_STR);
   $stmt->bindValue(':invThumbnail', $invThumbnail, PDO::PARAM_STR);
   $stmt->bindValue(':invPrice', $invPrice, PDO::PARAM_STR);
   $stmt->bindValue(':invStock', $invStock, PDO::PARAM_STR);
   $stmt->bindValue(':invSize', $invSize, PDO::PARAM_STR);
   $stmt->bindValue(':invWeight', $invWeight, PDO::PARAM_STR);
   $stmt->bindValue(':invLocation', $invLocation, PDO::PARAM_STR);
   $stmt->bindValue(':categoryId', $categoryId, PDO::PARAM_STR);
   $stmt->bindValue(':invVendor', $invVendor, PDO::PARAM_STR);
   $stmt->bindValue(':invStyle', $invStyle, PDO::PARAM_STR);
// Insert the data
   $stmt->execute();
// Ask how many rows changed as a result of our insert
   $rowsChanged = $stmt->rowCount();
// Close the database interaction
   $stmt->closeCursor();
// Return the indication of success (rows changed)
   return $rowsChanged;

错误讯息：

Notice: Undefined variable: invName in C:\CIT336\htdocs\acme\model\product-model.php on line 37

Notice: Undefined variable: invDescription in C:\CIT336\htdocs\acme\model\product-model.php on line 38

Notice: Undefined variable: invImage in C:\CIT336\htdocs\acme\model\product-model.php on line 39

Notice: Undefined variable: invThumbnail in C:\CIT336\htdocs\acme\model\product-model.php on line 40

Notice: Undefined variable: invPrice in C:\CIT336\htdocs\acme\model\product-model.php on line 41

Notice: Undefined variable: invStock in C:\CIT336\htdocs\acme\model\product-model.php on line 42

Notice: Undefined variable: invSize in C:\CIT336\htdocs\acme\model\product-model.php on line 43

Notice: Undefined variable: invWeight in C:\CIT336\htdocs\acme\model\product-model.php on line 44

Notice: Undefined variable: invLocation in C:\CIT336\htdocs\acme\model\product-model.php on line 45

Notice: Undefined variable: categoryId in C:\CIT336\htdocs\acme\model\product-model.php on line 46

Notice: Undefined variable: invVendor in C:\CIT336\htdocs\acme\model\product-model.php on line 47

Notice: Undefined variable: invStyle in C:\CIT336\htdocs\acme\model\product-model.php on line 48

Fatal error: Uncaught PDOException: SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'invName' cannot be null in C:\CIT336\htdocs\acme\model\product-model.php:50 Stack trace: #0 C:\CIT336\htdocs\acme\model\product-model.php(50): PDOStatement->execute() #1 C:\CIT336\htdocs\acme\products\index.php(158): insPro('Baseball', 'A round ball wi...', 'no-image.png', 'no-image.png', '5', '24', '6', '6', 'San Jose', '15', 'Diamond', 'Nylon') #2 {main} thrown in C:\CIT336\htdocs\acme\model\product-model.php on line 50

我不知道为什么变量将是未定义的，因为我在同一个文件中使用相同语法的类似函数正常工作。
我在代码中做错了什么？

Answer 1

您的变量未定义，因为该函数不知道存在这些变量。解决该问题的一种方法是将变量作为参数传递给函数。例如：

函数insPro（在这里传递变量）{your code goes here}

如果该方法在一个类中，并且这些变量在类范围内可用，那么您不必将它们作为参数传递。您可以将变量修改为如下所示：

$这 - ＆GT; invName

等等。

传递给SQL语句时，PHP变量未定义

1 个答案: