Question

我的程序应该在变量等于或小于0时停止，但是当程序运行时，如果变量大于0，代码将重置。

这是我的代码： Main.py

import random
import os 
import sys
global foodamount
foodamount = random.randint(1,10)
answer = str(input(("Right or Left")))
if answer == "Right" or answer == "right":
  #Check if foodamount is greater than 1, then if it is run cave.py
  foodamount = foodamount -1
  if foodamount < 1:
    print("You ran out of food. You lose")
    sys.exit()
  if foodamount > 0:
    os.system('python cave.py')

这是cave.py

＆＃13;

import random
import sys
import os
import main
print("Do you want to attack?")
attak = str(input(("Yes or No")))
if attak == "Yes" or attak == "yes":
  x = random.randint(1,2)
  if x == 1:
    os.system('python attack')
    
  if x == 2:
    
    print("You lose")
    sys.exit()
if attak == "no" or attak == "No":
  print("Do you leave the cave or go around the spider?")
  y = str(input("Leave or Around"))
  if y == "Leave" or y == "leave":
    main.foodamount = main.foodamount -1
    if main.foodamount < 1:
      print("You ran out of food. You lose")
      sys.exit()
    else:
      os.system('python test')

＆＃13;

当我在python中运行它时，程序从头开始，程序从头开始重新启动。

如果您能提供帮助，我们将不胜感激。

Answer 1

您的程序重新启动，因为导入错误。我不确定正确的输出应该是什么，但是我解决了你的代码，所以在做它应该做的事情之前它没有重新启动。我希望这有帮助。最后，您需要将两个文件放在同一目录中才能使用它们。

Main.py

import random
import os 
import sys
import cave

foodamount = random.randint(1,10)

def main():
    global foodamount

    answer = str(input(("Right or Left")))

    if answer == "Right" or answer == "right":
        #Check if foodamount is greater than 1, then if it is run cave.py
        foodamount = foodamount -1

        if foodamount < 1:
            print("You ran out of food. You lose", foodamount)
            sys.exit()
        elif foodamount > 0:
            os.system('python cave.py')        
main()

cave.py

import random
import sys
import os
from Main import *

print("You are in a cold section of the cave")
print("You see a spider in front of you")
print("Do you want to attack?")

attak = str(input(("Yes or No")))

if attak == "Yes" or attak == "yes":
    x = random.randint(1,2)
    if x == 1:
        os.system('python attack')     
    if x == 2:
        print("You lose")
        sys.exit()

if attak == "no" or attak == "No":
    print("Do you leave the cave or go around the spider?")
    y = str(input("Leave or Around"))
    if y == "Leave" or y == "leave":
        foodamount = foodamount -1
        if foodamount < 1:
            print("You ran out of food. You lose")
            sys.exit()
        else:
            os.system('python test')

Answer 2

如果满足某些条件，您似乎编写了一个在最后运行的脚本。不要这样做。相反，编写一个实现游戏逻辑的函数，并在“while”循环中运行该函数，如下所示：

def play_game():
    if the player dies:
        return False
    return True

while play_game():
    pass

Python：我的程序在函数检查变量＆gt;时重新启动。 0

2 个答案: