Question

我已经读取了一个输入文件并将每列提取到各个数组中，如下所示。

id = ["id\a_po87y", "id\ruio66", "id\rzd766", "id\ruio66", etc..]

store = ["Jack", "John_Marsha", "123_Smart_option", "John_Marsha", etc...]

group = ["leader", "leader_1", "fresher", "automation_dev", etc...]

id_details.txt （输入文件）

id\a_po87y  Jack    leader
id\ruio66   John_Marsha leader_1
id\rzd766   123_Smart_option    fresher
id\ruio66   John_Marsha automation_dev
....
etc

我应该如何以嵌套的方式迭代数组，以便在文件Jack_details中检查数组的第一个元素 - ＆＃39; id＆＃39;（id \ a_po87y）的preence。 txt（商店数组的第一个元素）应该从行名称中删除 - leader（同样是组数组的第一个数组元素）

同样，应检查id \ ruio66在2dn文件中的可用性 - 行id中的John_Marsha - leader_1，如果存在，则删除它。

等......

id[0]--> store[0]-->group[0]

id[1]--> store[1]-->group[1]

and so on

我的代码，但数组元素中跳过了值

file_dir = 'E:/ruby_work'

file = File.open("E:/ruby_work/id_details.txt", "r")
contents = file.each_line.map { |line| line.split("\t") }.transpose
id, file_name, group  = contents

id.each do |ids|
  puts "For ID: #{ids}"
  file_name.each do |name| 
    value = File.open("#{file_dir}/#{name}_details.txt")
    text = File.read(value)
    #puts text
    text.each_line do |el|
      group.each do |gr|
        if el.match(/#{gr}/) then 
          print "group row #{gr}\n"
          print "Its matching\n"
          replace = text.gsub( /#{Regexp.escape(ids)}\,\s/, '').gsub( /#{Regexp.escape(ids)}/, '' ).gsub /,\s*$/, ''
        else print "Not\n"
          print "group row #{gr}\n"
        end
        group.shift
      end 
    end
    file_name.shift
  end
end  
id.shift

我做错了什么？

Jack_details.txt

Joined on Feb 7, 2016
Created by: Solomon (ruio66) 

[groups]
leader_1 = id\rty67, id\mztrt, id\ruio66, ncr\025kc, id\a_po87y
automation = id\bzo0l4, ccr\poxz7j
automation_dev = id\ruio66

John_Marsha_details.txt

Joined on Jan 7, 2016
Created by: Jack Rondon 

[groups]
leader_1 = id\sop0r2, id\34_dev, id\mz4d5, id\ruio66
fresher = id\kzpo98, id\gz8sl7, id\cp0jxr, id\fzxlol, 
automation_dev = id\ruio66

输出

For ID: id\a_po87y
Not
group row leader

Not
group row leader_1

For ID: id\ruio66

Answer 1

如果我理解正确，也许你可以采取略微不同的方法：

考虑到这个

id[0]--> store[0]-->group[0]
id[1]--> store[1]-->group[1]

然后您不需要嵌套循环，您可以尝试仅循环一次并使用索引从每个数组中获取每个值，如下所示：

(0..id.size - 1).each do |i|
  puts "For ID: #{id[i]}"
  value = File.open("#{file_dir}/#{file_name[i]}_details.txt")
  text = File.read(value)

  text.each_line do |line|
    if line.match(/#{group[i]}/)
      print "group row #{group[i]}\n"
      print "Its matching\n"
      replace = text.gsub(/#{Regexp.escape(id[i])}\,\s/, '')
                    .gsub(/#{Regexp.escape(id[i])}/, '')
                    .gsub(/,\s*$/, '')
    else
      print "Not\n"
      print "group row #{group[i]}\n"
    end
  end
end

此代码假定id，file_name和group的大小始终相同。

在Ruby中的数组嵌套迭代期间跳过值

1 个答案: