Question

我正在使用HTML，CSS和Javascript处理地址簿。首先，我正在从JSON文件中读取一些数据条目。然后将这些条目存储到本地存储中。然后我通过名为 addToBook（）的函数从少数输入字段中获取用户的输入。然后将所有数据以JSON格式存储在名为 addressBook 的变量中。但是，当我尝试在名为 showaddressBook（）的函数中打印此数据时。它没有发生，因为它在chrome控制台中显示为Undefined。请参阅函数 showaddressBook（）中的这一行（ console.log（addressBook [i] .practice_name ）;）。任何想法的家伙。提前谢谢。

window.onload = function(){
var quickAddFormDiv = document.querySelector('.quickaddForm');  
var AddBtn = document.getElementById('Add');
// Form Fields
var lastname = document.getElementById('lastname');
var firstname = document.getElementById('firstname');
var email = document.getElementById('email');
var specialty = document.getElementById('specialty');
var practicename = document.getElementById('practicename');
// Divs etc.
var addBookDiv = document.querySelector('.addbook');

var addressBook = [];
var people;
localStorage.clear();
//--------------------------------------------------------------------
//To display the contents of JSON file
var xhttp = new XMLHttpRequest();
        xhttp.onreadystatechange = function() {
            if (this.readyState == 4 && this.status == 200) {
               var response = JSON.parse(xhttp.responseText);
               people = response.people;
               //var output = "";
               var str1 = '';
                for(var i = 0; i <people.length;i++){
                    str1 += '<div id="entry">';                 
                    str1 += '<div id="name"><p>' + people[i].last_name +', '+people[i].first_name+ '</p></div>';
                    str1 += '<div id="email"><p>' + people[i].email_address + '</p></div>';
                    str1 += '<div id="practicename"><p>' + people[i].practice_name + '</p></div>';                  
                    str1 += '<div id="specialty"><p>' + people[i].specialty + '</p></div>';
                    str1 += '<div id="del"><a href="#" class="delbutton" data-id="' + i + '">Delete</a></div>';
                    }
                for(var i = 0; i < people.length;i++){
                    var obj = new jsonStructure(people[i].last_name,people[i].first_name,people[i].email_address,people[i].specialty,people[i].practice_name);                  
                    addressBook.push(obj);                      
                    localStorage['addbook'] = JSON.stringify(addressBook);
                }

                document.getElementsByClassName("addbook")[0].innerHTML = str1;

            }
        };
        xhttp.open("GET", "people.json", true);
        xhttp.send();
        //------------------------------------------------------------------------------


        AddBtn.addEventListener("click", addToBook);
        //var addressBook = [];
        addBookDiv.addEventListener("click", removeEntry);

        function jsonStructure(lastname,firstname,email,specialty,practicename){
            this.lastname = lastname;
            this.lastname += ", "+firstname;                
            this.email = email;
            this.specialty = specialty;
            this.practicename = practicename;
        }
        function addToBook(){
            var isNull = lastname.value!='' && firstname.value!='' && email.value!='' && specialty.value!='' && practicename.value!='';
            if(isNull){
                // format the input into a valid JSON structure
                var obj = new jsonStructure(lastname.value,firstname.value,email.value,specialty.value,practicename.value);                 
                addressBook.push(obj);
                localStorage['addbook'] = JSON.stringify(addressBook);
                console.log(localStorage['addbook']);
                clearForm();
                showaddressBook();
            }
        }
        function removeEntry(e){
        // Remove an entry from the addressBook

            if(e.target.classList.contains('delbutton')){
                var remID = e.target.getAttribute('data-id');                   
                addressBook.splice(remID,1);
                localStorage['addbook'] = JSON.stringify(addressBook);
                showaddressBook();
            }
        }
        function clearForm(){
            var formFields = document.querySelectorAll('.formFields');
            for(var i in formFields){
                formFields[i].value = '';
            }
        }
        function showaddressBook(){
            if(localStorage['addbook'] === undefined){
                localStorage['addbook'] = '';
            } else {
                addressBook = JSON.parse(localStorage['addbook']);
                addBookDiv.innerHTML = '';
                var str = '';
                for(var i = 0; i <addressBook.length;i++){

                    str += '<div id="entry">';                  
                    str += '<div id="name"><p>' + addressBook[i].last_name +', '+addressBook[i].first_name+ '</p></div>';
                    str += '<div id="email"><p>' + addressBook[i].email_address + '</p></div>';
                    str += '<div id="practicename"><p>' + addressBook[i].practice_name + '</p></div>';                  
                    str += '<div id="specialty"><p>' + addressBook[i].specialty + '</p></div>';
                    str += '<div id="del"><a href="#" class="delbutton" data-id="' + i + '">Delete</a></div>';
                    console.log(addressBook[i].practice_name);
                }

            }
        }

        showaddressBook();
}

Answer 1

拼写错误错误

practice_name应为practicename
last_name应为lastname
first_name应为firstname
email_address应为email

<强>尝试：

for(var i = 0; i <addressBook.length;i++){
    str += '<div id="entry">';                  
    str += '<div id="name"><p>' + addressBook[i].lastname +', '+addressBook[i].firstname+ '</p></div>';
    str += '<div id="email"><p>' + addressBook[i].email + '</p></div>';
    str += '<div id="practicename"><p>' + addressBook[i].practicename + '</p></div>';                  
    str += '<div id="specialty"><p>' + addressBook[i].specialty + '</p></div>';
    str += '<div id="del"><a href="#" class="delbutton" data-id="' + i + '">Delete</a></div>';
    console.log(addressBook[i].practicename);
}

使用json html javascript的地址簿

1 个答案: