Question

例如

 my $starting_ip = '1.2.3.4';
 my $ending_ip   = '1.3.0.5';

我的输出将是

 1.2.3
 1.2.4
 1.2.5
 ..
 ..
 1.2.255
 1.3.0

我到目前为止尝试过：

use Socket;

my $startIp        = $ARGV[0];
my $endIp          = $ARGV[1];
my $start_address  = unpack 'N', inet_aton( $startIp );
my $finish_address = unpack 'N', inet_aton( $endIp );
my @f              = split( '\.', $endIp );
my $last_ip        = join( '.', $f[0], $f[1], $f[2] );

for ( my $address = $start_address;
        $address <= $finish_address;
        $address = $‌address + 255 ) {

    my $new_ip = inet_ntoa( pack 'N', $address );
    my @a = split( '\.', $new_ip );

    $new_ip = join( '.', $a[0], $a[1], $a[2] );

    print "$new_ip\n";
}

print "$last_ip\n";

无需考虑IP地址的最后部分。

Answer 1

喜欢这样吗？

sub ip_addr { $_[0] = pack "N", 1 + unpack "N", $_[0] }
my $starting_ip = 1.2.4.4;
my $ending_ip = 1.3.0.5;
   for ( $addresses = $starting_ip; $addresses le $ending_ip; ip_addr($addresses) ) {
      printf "%vd\n", $addresses;
   }

虽然还有很多其他方法，但我认为更好的选择是使用Net::IP

我需要使用Perl在给定范围内增加IP地址

1 个答案: