Question

在示例中，我需要检查日期是否包含在日期范围内，问题我只需要比较日期和月份而不是年份。感谢

$start_date = '2009-06-17';

$end_date = '2009-09-05';

$date_from_user = '2009-08-28';

check_in_range($start_date, $end_date, $date_from_user);


function check_in_range($start_date, $end_date, $date_from_user)
{
  // Convert to timestamp
  $start_ts = strtotime($start_date);
  $end_ts = strtotime($end_date);
  $user_ts = strtotime($date_from_user);

  // Check that user date is between start & end
  return (($user_ts >= $start_ts) && ($user_ts <= $end_ts));
}

Answer 1

使用date() format nd（连接到零填充日的月份）删除年份，然后您有一个3-4位数字，您可以比较不使用日期的年份：< / p>

function check_in_range($start_date, $end_date, $date_from_user)
{
    // Convert to timestamp
    $start_ts = date('nd', strtotime($start_date));
    $end_ts = date('nd', strtotime($end_date));
    $user_ts = date('nd', strtotime($date_from_user));

    // Check that user date is between start & end
    return (($user_ts >= $start_ts) && ($user_ts <= $end_ts));
}

事实上，您可以传递以下格式：

function check_in_range($start_date, $end_date, $date_from_user, $comparator = 'Ymd')
{
    // Convert to timestamp
    $start_ts = date($comparator, strtotime($start_date));
    $end_ts = date($comparator, strtotime($end_date));
    $user_ts = date($comparator, strtotime($date_from_user));

    // Check that user date is between start & end
    return (($user_ts >= $start_ts) && ($user_ts <= $end_ts));
}

check_in_range('2017-05-30', '2017-09-12', '2015-08-06', 'nd') // true
check_in_range('2017-05-30', '2017-09-12', '2015-05-06', 'nd') // false

http://codepad.org/Usnxkr9d

Answer 2

您可以使用PHP DateTime类。使用代码的示例：

    $start_date = '2009-06-17';
    $end_date = '2009-09-05';
    $x = new DateTime($start_date);
    $y = new DateTime($end_date);
    $dateDifference = $x->diff($y);
    // see difference in days using $dateDifference->d
    // see difference in months using $dateDifference->m

如何在不比较年份的情况下检查日期是否在日期范围内？

2 个答案: