Question

我有下面指定的数组

Base*

我有另一个数组，如下所示

Array
(
  [5] => Array
  (
    [id] => 5
    [first_name] => Diyaa
    [profile_pic] => profile/user5.png
  )

  [8] => Array
  (
    [id] => 8
    [first_name] => Raj
    [profile_pic] => profile/user8.png
  )

  [12] => Array
  (
    [id] => 12
    [first_name] => Vanathi
    [profile_pic] => profile/user12.png
  )

  [15] => Array
  (
    [id] => 15
    [first_name] => Giri
    [profile_pic] => profile/user15.png
  )

  [19] => Array
  (
    [id] => 19
    [first_name] => Mahesh
    [profile_pic] => profile/user19.png
  )
)

我希望来自第一个数组的Array ( [0] => 8 [1] => 15 [2] => 19 )，基于第二个数组值=＆gt; 8,15和19 。
所以我需要 Raj，Giri，Mahesh 作为逗号分隔字符串的输出怎么弄这个..？

Answer 1

此代码适用于您： -

$array1 = array_column($array, 'first_name','id');
$array2 = [8,15,19];
$names = array_intersect_key($array1, array_flip($array2));
$names = implode(',',$names);
echo $names;

Answer 2

试试这个：

$namesArr = [];
foreach ($wantedIds as $wantedId) {
    $namesArr[] = $array[$wantedId]['first_name'];
}
$namesStr = implode(',', $namesArr);

echo $namesStr; // Returns 'Raj,Giri,Mahesh'

我将$array和$wantedIds定义如下：

$array = [
    5 => [
        'id'          => 5,
        'first_name'  => 'Diyaa',
        'profile_pic' => 'profile/user5.png',
    ],
    8 => [
        'id'          => 8,
        'first_name'  => 'Raj',
        'profile_pic' => 'profile/user8.png',
    ],
    12 => [
        'id'          => 12,
        'first_name'  => 'Vanathi',
        'profile_pic' => 'profile/user12.png',
    ],
    15 => [
        'id'          => 15,
        'first_name'  => 'Giri',
        'profile_pic' => 'profile/user15.png',
    ],
    19 => [
        'id'          => 19,
        'first_name'  => 'Mahesh',
        'profile_pic' => 'profile/user19.png',
    ],
];

$wantedIds = [8, 15, 19];

Answer 3

我们正在使用array_column和array_intersect_key来获取所需的输出。

Try this code snippet here

$result=array();
$result=  array_column($array, "first_name","id");
$result=array_intersect_key ($result,  array_flip($values));
echo implode(",",$result);

Answer 4

试试这个：

>>> import pandas as pd
>>> import numpy as np

>>> a=pd.DataFrame([[18, 'F'],[50, 'M']],columns = ('Age','Sex'))
>>> print(a)

   Age Sex
0   18   F
1   50   M

>>> b=a
>>> print(b)

   Age Sex
0   18   F
1   50   M

>>> b.loc[b.index.max() + 1] = [30,'M']
>>> print(b)

   Age Sex
0   18   F
1   50   M
2   30   M

>>> print(a)

   Age Sex
0   18   F
1   50   M
2   30   M

>>> c=np.array([[18,'F'],[50,'M']])
>>> print(c)

[['18' 'F']
 ['50' 'M']]

>>> d=c
>>> print(d)

[['18' 'F']
 ['50' 'M']]

>>> d = np.append(d,[[30,'M']], axis=0)
>>> print(d)

[['18' 'F']
 ['50' 'M']
 ['30' 'M']]

>>> print(c)

[['18' 'F']
 ['50' 'M']]

Answer 5

<?php
    $abc = [
        ['id' => 5, 'firstname' => 'Diyya', 'profile_pic' => 'profile/user5.png'],
        ['id' => 8, 'firstname' => 'Raj', 'profile_pic' => 'profile/user8.png'],
        ['id' => 12, 'firstname' => 'Vanathi', 'profile_pic' => 'profile/user12.png']
    ];

    $d = [8, 5, 12];

    $output = [];
    foreach ($abc as $user) {
        if (in_array($user['id'], $d)) {
            $output [] = $user['firstname'];
        }
    }
    echo implode(",", $output);
?>

Answer 6

使用array_intersect_key()和array_column()时，还有其他明智的答案，但是，他们会以错误的顺序使用它们。应首先过滤数组，以便array_column()处理较小的数组。此外，由于您的子数组已经包含代表其中id值的键，因此无需使用index_key array_column()参数。这将是您可以做出的最简单，最直接的单线：

输入：

$array = [
    5 => [
        'id'          => 5,
        'first_name'  => 'Diyaa',
        'profile_pic' => 'profile/user5.png',
    ],
    8 => [
        'id'          => 8,
        'first_name'  => 'Raj',
        'profile_pic' => 'profile/user8.png',
    ],
    12 => [
        'id'          => 12,
        'first_name'  => 'Vanathi',
        'profile_pic' => 'profile/user12.png',
    ],
    15 => [
        'id'          => 15,
        'first_name'  => 'Giri',
        'profile_pic' => 'profile/user15.png',
    ],
    19 => [
        'id'          => 19,
        'first_name'  => 'Mahesh',
        'profile_pic' => 'profile/user19.png',
    ],
];
$search_keys=[8, 15, 19];

方法（Demo）：

echo implode(',',array_column(array_intersect_key($array,array_flip($search_keys)),'first_name'));

说明：

首先翻转$search_keys
然后使用array_intersect_key()过滤掉不需要的子阵列
然后使用array_column()创建first_name值
然后用逗号将它们粘在一起以创建一个字符串。

输出：

Raj,Giri,Mahesh

......这是未来SO读者应该学习和实施的答案。不幸的是，由于它的票数较少而且没有佩戴绿色标记，因此可能会被忽略。
:(

如何根据指定的给定数组值将数组值转换为逗号分隔字符串..？

6 个答案: