Question

我得到了JSON响应，我必须将数据存储在微调器中，但是当我选择Alabama时，＆＃34; AL＆＃34;在toast msg它应该来。我该怎么办？

{
    "status" : "success",
    "data" : {
        "AL" : "Alabama",
        "AK" : "Alaska"
    }
}

先谢谢你

Answer 1

试试我的朋友

/system/build.prop

Answer 2

你好尝试这个，如果它有帮助

public class MainActivity extends AppCompatActivity implements AdapterView.OnItemSelectedListener {
    List<City>cityList= new ArrayList<>();
    List<String> cityListName= new ArrayList<>();
    Spinner spnCity;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        spnCity=(Spinner)findViewById(R.id.spnCity);
        String response="{\"status\":\"success\",\"data\":{\"AL\":\"Alabama\",\"AK\":\"Alaska\"}}";
        try {
            JSONObject iObject=new JSONObject(response);
            JSONObject data=iObject.getJSONObject("data");
            Iterator<String> iter = data.keys();
            while (iter.hasNext()) {
                String key = iter.next();
                try {
                    Object value = data.get(key);
                    cityListName.add(value.toString());
                    cityList.add(new City(key,value.toString()));
                } catch (JSONException e) {
                }
            }
            ArrayAdapter<String> dataAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, cityListName);

            // Drop down layout style - list view with radio button
            dataAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);

            // attaching data adapter to spinner
            spnCity.setAdapter(dataAdapter);
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }


    @Override
    public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
        String item = adapterView.getItemAtPosition(i).toString();
        for (int j = 0; j < cityList.size(); j++) {
            if(cityList.get(j).getCityName().equals(item)){
                Toast.makeText(adapterView.getContext(), "Selected: " + item +" "+cityList.get(j).getCityName(), Toast.LENGTH_LONG).show();
            }
        }
        // Showing selected spinner item

    }

    @Override
    public void onNothingSelected(AdapterView<?> adapterView) {

    }
}

Answer 3

尝试

JSONObject jsonObject = new JSONObject(jsonString);
String status = jsonObject.getString("status");
List<String> data = new ArrayList<String>();
JSONArray array = jsonObject.getJSONArray("data");
Iterator<String> keys = jsonObject.keys();
while (keys.hasNext()) {
    String key = keys.next();
    String value = jsonObject.getString(key);
}

阅读Android中的JSON响应

3 个答案: