如何在oozie 4.2.0上运行spark动作(pyspark脚本)?

时间:2017-05-26 04:10:16

标签: python apache-spark pyspark environment-variables oozie

当我提交一个python脚本作为jar来激发oozie中的动作时,我看到以下错误:

Traceback (most recent call last):
  File "/home/hadoop/spark.py", line 5, in <module>
    from pyspark import SparkContext, SparkConf
ImportError: No module named pyspark
Intercepting System.exit(1)

虽然我可以看到我的本地FS存在pyspark库:

$ ls /usr/lib/spark/python/pyspark/
accumulators.py     heapq3.py           rdd.py              statcounter.py
broadcast.py        __init__.py         rddsampler.py       status.py
cloudpickle.py      java_gateway.py     resultiterable.py   storagelevel.py
conf.py             join.py             serializers.py      streaming/
context.py          ml/                 shell.py            tests.py
daemon.py           mllib/              shuffle.py          traceback_utils.py
files.py            profiler.py         sql/                worker.py

我知道在像https://issues.apache.org/jira/browse/OOZIE-2482这样的oozie上运行pyspark存在问题,但我看到的错误与JIRA票证不同。

此外,我在我的工作流程定义中将--conf spark.yarn.appMasterEnv.SPARK_HOME=/usr/lib/spark --conf spark.executorEnv.SPARK_HOME=/usr/lib/spark作为spark-opts传递。

以下是我的示例应用程序供参考:

job.properties

masterNode ip-xxx-xx-xx-xx.ec2.internal
nameNode hdfs://${masterNode}:8020
jobTracker ${masterNode}:8032
master yarn
mode client
queueName default
oozie.libpath ${nameNode}/user/oozie/share/lib
oozie.use.system.libpath true
oozie.wf.application.path /user/oozie/apps/

workflow.xml($ {nameNode} / user / oozie / apps /)

<workflow-app name="spark-wf" xmlns="uri:oozie:workflow:0.5"> 
    <start to="spark-action-test"/> 
    <action name="spark-action-test"> 
        <spark xmlns="uri:oozie:spark-action:0.1"> 
            <job-tracker>${jobTracker}</job-tracker> 
            <name-node>${nameNode}</name-node> 
            <configuration>  
                <property> 
                    <name>mapred.compress.map.output</name> 
                    <value>true</value> 
                </property> 
            </configuration> 
            <master>${master}</master> 
            <mode>${mode}</mode>
            <name>Spark Example</name>
            <jar>/home/hadoop/spark.py</jar>
            <spark-opts>--driver-memory 512m --executor-memory 512m --num-executors 4 --conf spark.yarn.appMasterEnv.SPARK_HOME=/usr/lib/spark --conf spark.executorEnv.SPARK_HOME=/usr/lib/spark --conf spark.yarn.appMasterEnv.PYSPARK_PYTHON=/usr/lib/spark/python --conf spark.executorEnv.PYTHONPATH=/usr/lib/spark/python --files ${nameNode}/user/oozie/apps/hive-site.xml</spark-opts>
        </spark> 
        <ok to="end"/> 
        <error to="kill"/> 
    </action> 
    <kill name="kill"> 
        <message>Action failed, error message[${wf:errorMessage(wf:lastErrorNode())}]</message> 
    </kill> 
    <end name="end"/> 
</workflow-app>

spark.py(at / home / hadoop /)

# sc is an existing SparkContext.
from pyspark import SparkContext, SparkConf
from pyspark.sql import HiveContext
conf = SparkConf().setAppName('test_pyspark_oozie')
sc = SparkContext(conf=conf)

sqlContext = HiveContext(sc)


sqlContext.sql("CREATE TABLE IF NOT EXISTS src (key INT, value STRING)")

根据这里的建议 - http://www.learn4master.com/big-data/pyspark/run-pyspark-on-oozie,我也确实在我的$ {nameNode} / user / oozie / share / lib文件夹下放了以下两个文件:py4j-0.9-src.zip pyspark.zip。 / p>

我正在使用单节点YARN群集(AWS EMR)&amp;试图找出我可以在我的oozie应用程序中将这些pyspark模块传递给python。任何帮助表示赞赏。

1 个答案:

答案 0 :(得分:2)

您收到No module named error,因为您的配置中未提及PYTHONPATH。使用--confPYTHONPATH=/usr/lib/spark/python中再添加一行。我不知道如何在oozie工作流定义中设置此PYTHONPATH,但在配置中添加PYTHONPATH属性肯定会解决您的问题。