我试图在蛋糕php中加入3个表。 我会缩短我的表格以使其变得简单。
table_users(
id int primary key,
username varchar(10),
password varchar(10),
)
table_details(
id int primary key,
user_id int, //fk of table_users.id
//more fields here
)
table_ot(
id int primary key,
user_id int, //fk of table_users.id
//more fields here
)
我计划使用user_id加入table_details和table_ot。 在cake bake生成的模型中,table_details连接table_users,table_ot是table_users。
但是table_details没有加入table_ot。 这是table_details和table_ot的内容。
$this->belongsTo('table_users', [
'foreignKey' => 'user_id',
'joinType' => 'INNER'
]);
在控制器中也尝试过这个仍然无法正常工作。
$Overtime = $this->table_ot->find()->all(array('joins' =>
array(
'table' => 'table_table_details',
'alias' => 'table_table_details',
'type' => 'full',
'foreignKey' => false,
'conditions'=> array('table_ot.user_id = table_table_details.user_id')
)
));
任何建议..请帮助
答案 0 :(得分:0)
正如您在问题中指出的那样,您已经设置了表关联。所以你可以这样编写你的查询:
http://97.987.98.987
使用例如toArray()执行此查询后,您可以像这样访问与table_ot关联的table_details记录:
$this->table_ot->find("all",[
"contain" => [
"table_users" => ["table_details"]
]
]);
作为替代方案,我建议你尝试加入这两个表:
$detailId = $results[0]->table_users->table_details->id;
此处列出了每种关联类型的所有可用选项:https://book.cakephp.org/3.0/en/orm/associations.html
答案 1 :(得分:0)
You have to add another field in table_ot to join with table_details according to cake convention. Because you have a foreign just to join with user table.
table_ot(
id int primary key,
user_id int, //fk of table_users.id
details_id int, //fk of table_details.id
//more fields here
)
Then add this code in table of table_ot
$this->belongsTo('table_details', [
'foreignKey' => 'details_id',
'joinType' => 'INNER'
]);