Question

问题在于，何时使用带有change_admin表单中的选项的select，它不会仅对应该更改的产品进行更改，而且对于同一商店中的其他产品也不会更改，我不希望这样。我工作了4个小时，但我找不到解决方案。

这是一个想法（我知道代码不是代码，但它提供了我想要实现的目标以及如何实现）：

    <form method="post">
    <select name="store">
        <option value="1">amsterdam</option>
        <option value="2">rotterdam</option>
        <option value="3">den haag</option>
    </select>
    <input type="submit" name="store" id="store" value="change city" />
</form>
<php
sql="get * from selected store"
foreach{item in selected store}{
    sql="get name for looped item"
    sql="get all admins"
    echo"all given info in td"
    if{the item has not been processed by a admin}{
        <from method="post">
            <select name="adminchange" onchange="submit()">
                <option value="null">not processed</option>
                foreach(for each admin make a option){
                    <option value="admin email">admin name</option>
                };
            </select>
        </form>
    }else{
        echo 'the name of the admin that processed it';
    };
};
 if (isset($_POST["chosen_admin"])) {
                $admin = the admin it was changed to;
                $productid = product where the admin was change;
                $sql = "UPDATE products SET admin = '$admin' WHERE product_id='$productid'";
                $stmt = $conn->prepare($sql);
                $stmt->execute();  
 };?>

以下是我在我的网站上使用的代码（这是真正的代码，所以如果你看到错误，请告诉我，所有提示都是受欢迎的，因为这是我正在研究的一个外容。）：

<form method="POST" >
    <select name="winkel">
        <option value="1">flowerpower amsterdam</option>
        <option value="2">flowerpower den Haag</option>
        <option value="3">flowerpower Rotterdam</option>
    </select>
     <input type="submit" name="store" id="submit" value="nu bestellen" />
     </form>
    <table border="1">
        <tr>
            <th><p>artikel</p></th>
            <th><p>aantal</p></th>
            <th><p>afhaler</p></th>
            <th><p>afhaal tijd</p></th>
            <th><p>afgehandeld door</p></th>
        </tr>
<?php
    if (isset($_POST["store"])) {
      $sql = "SELECT * FROM verkocht WHERE locatie_ophalen = ". $_POST["winkel"] ;
    } else {
      $sql = "SELECT * FROM verkocht WHERE locatie_ophalen = 1";
    }
    $result = $conn->query($sql);
    foreach($result as $verkocht){
        $sql = "SELECT  product_naam FROM producten WHERE product_id = ?";
        $stmt = $conn->prepare($sql);
        $stmt->execute(array($verkocht["product_id"]));
        $gegevens = $stmt->fetch(PDO::FETCH_ASSOC);
        $sql = "SELECT * FROM users WHERE medewerker = 1";
        $admins = $conn->query($sql);

        echo '<tr><td>'. $gegevens["product_naam"]. '</td>
        <td>'. $verkocht["verkocht_aantal"].'</td>
        <td>'. $verkocht["verkocht_klant"].'</td>
        <td>'.$verkocht["tijd_ophalen"].'</td>
        <td>';
        if($verkocht["medewerker_verwerkt"] == 0){
            echo'<form method="POST"><select name="chosen_admin" onchange="submit()">
            <option value="null">nog niet verwerkt</option>';
            foreach($admins as $admin){                   
            echo'<option value="'. $admin["email"].'">'. $admin["voornaam"].' '. $admin["achternaam"].'</option>';      
            };
        }else{
            echo $verkocht["medewerker_verwerkt"];
        };

            echo '</select></form>';
            echo '</td></tr>';
    };
 if (isset($_POST["chosen_admin"])) {
                $medewerker = $_POST["chosen_admin"];
                $verkoopid = $verkocht["verkocht_id"];
                $sql = "UPDATE verkocht SET medewerker_verwerkt = '$medewerker' WHERE verkocht_id='$verkoopid'";
                $stmt = $conn->prepare($sql);
                $stmt->execute();  
 };?>
</table>

php在foreach循环中提交更新数据库

0 个答案: